The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.Which equations can be used to solve for y, the length of the room? Check all that apply.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0

Answers

Answer 1
Answer:

Answer:

Option B , C  and E are correct

y^2-5y =750

750 -y(y-5)=0

(y+25)(y-30)=0

Step-by-step explanation:

Given : Area of rectangular room is 750 square feet.

Width of the room is 5 feet less than the length of the room.

Let y be the length of the room

then,

As per the given condition

width of the room is: y-5

Area of rectangle is multiply the length by its width.

Area of rectangle = length * width

Substitute the given values in above formula we get;

750 = y(y-5)                            ......[1]

or we can write this as;

750 -y(y-5)=0

[1] ⇒y(y-5) =750  or

y^2-5y =750 or

y^2-5y-750=0

y^2-25y+30y-750=0

(y+25)(y-30)=0

Therefore, the equation which can be used to solve for y are;

y^2-5y =750 , 750 -y(y-5)=0  and (y+25)(y-30)=0




Answer 2
Answer: Hello,

A:False
B:True
C:True
D:False
E:True



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Answers

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Answers

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