b. 2 times
c. 1/4
d. 4 times
Answer : The correct option is, (d) 4 times
Solution :
According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.
Formula used :
where,
F = electrostatic force of attraction or repulsion
= Coulomb's constant
and are the charges
r = distance between two charges
First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'
..........(1)
Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.
...........(2)
Equation equation 1 and 2, we get
Therefore, the force exerted between S and q is 4 times the force exerted between S and p.
I believe the answer is "4 times".
By utilizing principles of projectile motion, it is found that the football clears the crossbar by approximately 10.75 meters.
To determine by how much the ball clears or falls short of clearing the crossbar, we need to use the physics principles of projectile motion. The maximum height 'h' of the football can be given by equation of motion: h = (v²sin²θ) / (2g), where 'v' is the initial velocity, 'g' is the acceleration due to gravity and 'θ' is the angle of projection.
Substituting the given values: h = [(20)²sin²53°] / (2*9.8) ≈ 13.8 m above the ground when it was kicked. However, the football was kicked from ground level, so we need to subtract the height of the crossbar from this value, which is 3.05 m. Thus, the ball clears the crossbar by approximately: 13.8 - 3.05 = 10.75 m.
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that is false because even boys who are nerds or poor and even gay are victims of domestic violence.