Find the radical equivalent of 272/3 and compute it?

Answers

Answer 1
Answer:

Answer: The radical equivalent of 27^{(2)/(3)}\n is 9.

Step-by-step explanation:

Since we have given that

27^{(2)/(3)}\n

We need to find the radical equivalent.

so, we will use the "Exponential law":

(a^m)^{(1)/(n)}=a^{(m)/(n)}

so, it becomes,

27^(2)/(3)\n\n=(3^3)^(2)/(3)\n\n=(3^(3)/(3))^2\n\n=3^2\n\n=9

Hence, The radical equivalent of 27^{(2)/(3)}\n is 9.


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For each pair of mathematical expressions, determine if the expressions have equal values. Select each pair of expressions that came out to be equal.Please note, not all pairs will come out to the same value. We want you to determine if the expressions in each answer option have the have the same value.

Question options:

36÷3+3 and 22+2
36
÷
3
+
3

a
n
d

2
2
+
2

−(23)2and 49
-
(
2
3
)
a
n
d

4
9

8(−9) and −12−60
8
(
-
9
)

a
n
d

-
12
-
60

1+24 and 1−14

Answers

this doesn’t make sense you can really see the options

Solve the system using elimination.

5x + 8y = –29
7x – 2y = –67

Answers

7x-2y+-67
multiply both sides of the bottom by 4 and add                                            5x+8y=-29 
 28x-8y=268
 
  33x=-297
   x=-9 


5(-9) +8y= -29 
-45 +8y =-29 
8y= 16 
y=2

Stephanie is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd} and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∩ B.{1,3,5,7,9,11}
{1,3,9}
{3,9}
{3,9,12}

Answers

The outcomes of rolling two cubes are shown in the table below (the outcomes is added up). The members of A are circled while the members of B are boxed. The members of A that also members of B is both circled and boxed.

P(A) = {3, 5, 7, 9, 11}
P(B) = {3, 6, 9, 12}
P(A∩B) = {3,9}

The intersection between the sets are the values that are common to both sets that is {3, 9}

What are sets?

Sets are arrangement of values of elements in a specified way.

Given the following sets

A = {1, 3,5, 7, 9, 11}

B = {3, 6, 9,12}

The intersection between the sets are the values that are common to both sets, hence;

A ∩ B = {3, 9}

Learn more on set here: brainly.com/question/5660357

#SPJ5

Solve the equation: Show work step by step

-14=-5+3c

Answers

-14 = -5 + 3c

First, regroup your terms. / Your problem should look like: -14 = 3c - 5
Second, add 5 to both sides. / Your problem should look like: -14 + 5 = 3c
Third, simplify -14 + 5 to -9. / Your problem should look like: -9 = 3c
Fourth, divide both sides by 3. / Your problem should look like: -(9)/(3) = c
Fifth, simplify the fraction to 3. / Your problem should look like: -3 = c
Sixth, switch your sides. / Your problem should look like: c = -3

Answer: c = -3


−14=−5+3c

−14=3c−5

Flip the equation.

3c−5=−14

Add 5 to both sides.

3c−5+5=−14+5

3c=−9

Divide both sides by 3.

3c/3=−9/3

c=−3

PLEASE HELP I'LL GIVE BEAINLIEST!!!!! ​

Answers

Answer:

9 2/3

Step-by-step explanation:

50=6a-8

+8     +8

58=6a

/6    /6

9  2/3=a

Suppose 6 is a factor of ab, where a and b are natural numbers. Make a valid argument to explain why each assertion is true or provide a counterexample to show that an assertion is falsea. 6 must be a factor of a or of b
b. 3 must be a factor of a or of b
c. 3 must be a factor of a and of b

please help and show work

Answers

example
if ab=6
and a=3
b=2

a. 6 must be factor of 3 or 2 FALSE
b. 3 must be a factor of 3 OR 2 TRUE
c. 3 must be a factor of 3 AND 2 FALSE



B is true