A camper attaches a rope from the top of her tent, 4 ft above the ground, to give it more supporting she takes a rope to the ground 6 feet from the middle of the tent, about how long is the rope from the ground to the tent

Answers

Answer 1

Answer:

The rope is tied 4.5 ft from the center of the tent.

What is the Pythagorean theorem?

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal to the square of the sum of the other two sides. According to this statement, the areas of the squares on the other two sides add up to the size of the square whose side is the hypotenuse.

The value of c is calculated as:-

a² + b² = c²

It is given the rope is attached to the top of her tent and the rope the camper takes is 6ft long and tied to the ground. A right-angle triangle is formed with hypotenuse as 6 ft and height that one of the legs of the right triangle as 4 ft.

The length of the rope from the ground to the tent will be calculated as below:-

By Pythagoras's Theorem :

a² + b² = c²

4² + b² = 6²

b² = 36 - 16 = 20

b = √20 = 4.47 ft.

Therefore, the rope is tied 4.5 ft from the center of the tent.

To know more about the Pythagorean theorem follow

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Answer 2

Answer:

Answer:The rope is tied 4.5 ft from the center of the tent.

Step-by-step explanation:

It is given the rope is attached from top of her tent and the rope the camper takes is 6ft long tied to the ground.A right angle triangle is formed with hypotenuse as 6 ft and height that is one of the legs of the right triangle as 4 ft . We need to find the other leg of the right triangle which will represent the ground distance from the middle of tent to the point where the rope is tied .

By Pythagoras's Theorem :

$a^(2) +b^(2) =c^(2)$

Where a and b are the legs and c the hypotenuse of the right triangle.

Substituting the values of a and c we have:

$4^(2) +b^(2) =6^(2)$

or $16+b^(2) =36$

$b^(2) =36-16=20.$

Tabing root of both sides b=4.47.

The rope is tied 4.5 ft from the center of the tent.

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Factor 2m2 + 27m + 70

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The area of a rectangular field is given by the trinomial t2 – 4t – 45. The length of the rectangle is t + 5. What is the expression for the width of the field?

A. t – 9
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Answers

Hello,

1) x²+11x+24=x²+8x+3x+24=x(x+8)+3(x+8)=(x+8)(x+3) ANSWER C

2)2m²+27m+70=2m²+20m+7m+70=2m(m+10)+7(m+10)
=(m+10)(2m+7) ANSWER A

3)g²-64=(g-8)(g+8) ANSWER B

4) 49t²-9=(7t-3)(7t+3) answer C

5)
t²-4t-45=t²+5t-9t-45=t(t+5)-9(t+5)=(t+5)(t-9)

l=t+5
==>w=t-9
answer A

Which measurement is equivalent to 5 quarts?25 cups
40 fl. oz.
10 pints
1.5 gallons

Answers

If you would like to know which measurement is equivalent to 5 quarts, you can calculate this using the following steps:

1 quart = 4 cups
1 quart = 2 pints
1 quart = 32 fl. oz.
1 quart = 0.25 gallons

5 quarts = 5 * 4 cups = 20 cups
5 quarts = 5 * 2 pints = 10 pints
5 quarts = 5 * 32 fl. oz. = 160 fl. oz.
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Equivalent: 10 pints.

The dataset below represents the population densities per square mile of land area in 15 states in the 2010 U.S. Census. What is the interquartile range?

Answers

Answer:

The Interquartile range is 188

Step-by-step explanation:

Missing Data:

1,19,35,43,49,55,63,94,105,110,175,231,239,351,738

Required

Determine the Interquartile range (IQR)

The given data is ordered already.

First, we need to determine the median

For odd number of data

Median = ½(n + 1)th

In this case, n = 15; so

Median = ½(15 + 1)th

Median = ½(16)th

Median = 8th

This implies that the median is at the 8th position.

So, we have:

1,19,35,43,49,55,63 ----> Lower

(94) ---- Median

105,110,175,231,239,351,738 ---- Upper

Next, we determine the median of the lower and upper sets.

These are called lower quartile (Q1) and upper quartile (Q3) respectively

Lower: 1,19,35,43,49,55,63

Number of data, n = 7

Q1 = ½(n + 1)th

Q1 = ½(7 + 1)th

Q1 = ½(8)th

Q1 = 4th position

From the list of data in the lower set,

Q1 = 43

Upper: 105,110,175,231,239,351,738

Number of data, n = 7

Q3 = ½(n + 1)th

Q3 = ½(7 + 1)th

Q3 = ½(8)th

Q3 = 4th position

From the list of data in the upper set,

Q3 = 231

IQR is then calculated as thus:

IQR = Q3 - Q1

IQR = 231 - 43

IQR = 188

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Answers

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