Answer:
Step-by-step explanation:
Well the question you should be asking first is....what is part a? Because if you put that picture up i could mostly help sooo
Answer:
Option A is correct that is $15.
Step-by-step explanation:
Caroline bought 20 shares of stock at , and after 10 months the value of the stocks was .
We need to calculate the profit which is the difference of the two values of the stock.
The above value is for 1 share we have to calculate it for 20 shares
So, we will multiply it with 20 we get:
Therefore, Option A is correct that is $15.
1 4/7x 2/5
The required solution to the given fractions is 22/35.
A fraction is defined as a numerical representation of a part of a whole that represents a rational number.
The fractions are given in the question following:
1 4/7 × 2/5
To multiply fractions, you multiply the numerators (the top numbers) to get the numerator of the answer and multiply the denominators (the bottom numbers) to get the denominator of the answer.
As per the question, we have
⇒ 1 4/7 × 2/5
Convert mixed numbers to fractions
⇒ 11/7 × 2/5
⇒ (11 × 2)/(7 × 5)
Apply the multiplication operation, and we get
⇒ 22/35
Therefore, the answer is 22/35.
Learn more about the fraction here:
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Answer:
22/35
Step-by-step explanation:
Answer:
a) The probability is 0.04
b) The probability is 0.36
c) The pprobability is 0,25
d) The probability is 0.09
Step-by-step explanation:
Lets calculate areas:
the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.
a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04
b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.
c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25
d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.