Atoms bond by sharing valence electrons.
- When [S] << Km, the reaction is second order and V0 depends on [S] and [Et].
- Their kcat is a second order rate constant.
- The lower their Km, the better they recognize their substrate, but the lower their reaction rate.
- When [S] << Km, V0 depends on [S] and [Et].
Answer:
1. True. 2. True. 3. Not true. 4. True. 5. True
Explanation:
1. Yes, because if the amount of substrate i much greater than of competitive inhibitor then the probability of substrate to bind to ferment is much higher than of inhibitor (if we have noncompetitive inhibitor it damages the structure of active site and the substrate concentration does not have a role in reaction rate).
2. Yeah, because then the michaelis-menten equation will transform into [tex} V0=(kcat*[E]*[S])/Km [/tex] and it is a second order equation.
3. No, because it is measured in sec-1 and that means it is 1 rate constant.
4. True, if the lower Km the better is binding and due to that rate is slower because it's harder for substrate to unbind.
5. The same as question two.
CaCl2
Ca(NO3)2
Ca(OH)2
CaSO4
BaCl2
Answer:0.0008 mmg
Explanation:
Answer:
The freezing point depression of solvent is 0.8265 K.
Explanation:
Mass of glucose = 250 g
Mass of solvent = 20.0 g = 0.020 kg
Molal depression water constant of water, = 1.86 K kg/mol
Molality of the solution =
Normal freezing point of water =
Freezing point of solution =
The freezing point depression of solvent is 0.8265 K.
Answer:
10.7 g of KOH
Explanation:
First of all, we determine the reaction:
2K (s) + 2H₂O(l) → H₂(g) + 2KOH(aq)
We convert the mass of K, to moles → 7.5 g . mol/39.1 g = 0.192 moles
Ratio is 2:2, so the moles I have of K must produce the same moles of KOH. In this case, the produces moles of KOH are 0.192 moles.
We convert the moles to mass, to finish the answer:
0.192 mol . 56.1g /1mol = 10.7 g of KOH
1- 5 grams O2 / 1 gram C3H8
2- 5 moles O2 / 1 mole C3H8
3- 10 grams O2 / 11 grams C3H8
4- 10 moles O2 / 11 moles C3H8
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 5 moles oxygen / 1 mole propane. The correct option is option C among all the given options.
The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.
The balanced equation for the given chemical reaction can be given as
CH + 5O 3CO + 4HO
Stoichiometry represents the number of number of moles of reactant and products. The mole ratio between oxygen and propane is 5:1. the correct option isoption 2.
Therefore, 5 moles oxygen / 1 mole propane. The correct option is option C among all the given options.
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