If Susie is 14, what was her age x years ago? x - 14 14 - x 14x

Answers

Answer 1

Answer: "If Susie is 14, what was her age x years ago?"

that would be 14 minus x
or
14 - x

Answer 2

Answer: I think the correct answer would be B. 14-x

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A pool is being drained at a constant rate. The amount of water is a function of the number of minutes the pool has been draining, as shown in the table. Write an equation in slope-intercept form that represents the function. Then find the water in the pool after two and a half hours. Time (mi) 12--------20------50
Volumne (gal) 4962--4754--3974

Answers

The equation in the slope-intercept form is $y=-26x+5274$ and there will be $1374$ gallons of water in the pool after $2$ and a half hours.

The equation of a line that passes through two points $(x_1, y_1)$ and $(x_2, y_2)$ is $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$ .

Take points $(12, 4962)$ and $(20, 4754)$ .

Here, $x_1=12, y_1=4962, x_2=20, y_2=4754$ .

The equation is :

$(y-4962)=(4754-4962)/(20-12)(x-12)$

$(y-4962)=(-208)/(8)(x-12)$

$8(y-4962)=-208(x-12)$

$8y-39696=-208x+2496$

$208x+8y-39696-2496=0$

$208x+8y-42192=0$

$8y=-208x+42192$

$y=-(208)/(8)x+(42192)/(8)$

$y=-26x+5274.$

The slope intercept form is $y=mx+c$ , where $m$ is the slope and $c$ is the $y$ -intercept.

After $2$ and a half hours or $150$ minutes.

Put $x=150$ in the equation $y=-26x+5274.$

$y=-26* 150+5274$

$y=-3900+5274$

$y=1374$

So, there will be $1374$ gallons of water in the pool after $2$ and a half hours.

Learn more about slope-intercept form here:

brainly.com/question/21366542?referrer=searchResults

Answer:

Using the first two values in the table, we can first find the slope to write an equation of a line, so we have

[4754 - 4962 ] / [20 - 12 ] = -26

So we have

y - 4754 = -26(x - 20)

y - 4754 = -26x + 520

y = -26x + 5274

Let's confirm that the amount after 50 minutes is correct

y = -26(50) + 5274 = 3974

So after 2 + 1/2 hrs (150 min) we have

y = -26(150) + 5274 = 1374 gallons

Step-by-step explanation:

The function f(t) = 4t2 − 8t + 7 shows the height from the ground f(t), in meters, of a roller coaster car at different times t. Write f(t) in the vertex form a(x − h)2 + k, where a, h, and k are integers, and interpret the vertex of f(t).f(t) = 4(t − 1)2 + 3; the minimum height of the roller coaster is 3 meters from the ground
f(t) = 4(t − 1)2 + 3; the minimum height of the roller coaster is 1 meter from the ground
f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 1 meter from the ground

Answers

f(t) = 4t² - 8t + 7

f(t) = 4(t² - 2t) + 7
f(t) - 7 = 4(t² - 2t - __)

t² ⇒ t * t
2t ⇒ 2 * 1t
1² ⇒ 1 * 1

f(t) - 7 + 4(1) = 4(t² - 2t + 1)

(t-1)(t-1) = t(t-1) -1(t-1) = t² - t - t + 1 = t² - 2t + 1

f(t) = 4(t-1)² + 3

Answer:

A f(1) =4(1)^2 – 8(1) +7 min height 3

Step-by-step explanation:

The function is a parabola, and the problem asks to transform the equation into f(t)=a(x-h)2 + k

Given f(t) = 4t2 -8t +7

= (4t2 - 8t + 4) + 7 - 4

=4 (t2 - 2t + 1) + 3

= 4 (t-1) 2 +3

This removes C and D from the viable choices.

Differentiating the f(t),

f’(t) = 8t – 8, the maximum/minimum value occurs at f’(t) = 0

0 = 8t – 8

t = 1

determining if maximum or minimum, f”(t) > 0 if minimum, f”(t) < 0 maximum

f”(t) = 8 > 0, therefore minimum

f(1) =4(1)^2 – 8(1) +7

= 3

Therefore, minimum height is 3.

What is the average of the inte:ers from 25 to 41

Answers

To see this, notice that if you remove 25 and 41 from your sequence, then the average of the remaining terms is still given by the average of the extreme terms 26+40/2=33.

6x + 4x - 1 = 2(5x + 4)

Answers

Answer:NO SOL

Step-by-step explanation:

Simplifying and applying the distributive property, we get 10x-1=10x+8. Subtracting 10x from both sides, we get -1 = 8, which is impossible. Thus, there are no solutions.

5. What is a cubic polynomial function in standard form with zeros 1, –2, and 2? (1 point)= x3 + x2 – 3x + 4
= x3 + x2 – 4x – 2
= x3 + x2 + 4x + 4
= x3 – x2 – 4x + 4