Answer:
Given the equation:
shows the relationship between a planet's orbital period T and the planet's mean distance from the sun, A in Astronomical units
then:
For planet X:
Orbital period is:
.....[1]
As per the statement:
If planet Y is k times the mean distance from the sun as planet X.
⇒ A planet Y= kA mean distance from the sun as planet X.
then orbital period of Planet Y is:
....[2]
Divide equation [2] by [1] we have;
Simplify:
or
Therefore, the orbital period is increased by factor
To determine the theoretical probabilities, we'll analyze the different possible outcomes for each case.
Total number of cards = 40 (5 cards for each number from 2 to 9)
a) Sum is 12:
There are several combinations of cards that can result in a sum of 12:
Total favorable outcomes = 6 (since there are 6 possible combinations)
Total possible outcomes (since you're drawing two cards) = 40 * 40 = 1600
Probability (sum is 12) = (Number of favorable outcomes) / (Total possible outcomes)
Probability (sum is 12) = 6 / 1600 = 0.00375
b) Difference is less than 5:
There are several combinations of cards that can result in a difference less than 5:
Total favorable outcomes = 14
Total possible outcomes = 1600
Probability (difference is less than 5) = 14 / 1600 = 0.00875
c) Product is odd:
For the product to be odd, one or both of the numbers drawn must be odd. Since there are five odd numbers (3, 5, 7, 7, 9), and each number has five cards, the total number of favorable outcomes is 5 + 5 + 5 + 5 + 5 = 25.
Total possible outcomes = 1600
Probability (product is odd) = 25 / 1600 = 0.015625
To summarize:
b) he z-statistic is 1.68, so the null hypothesis cannot be rejected.
c) The z-statistic is 1.85, so the null hypothesis should be rejected.
d) The z-statistic is 4.6, so the null hypothesis should be rejected.
Answer:
its B
Step-by-step explanation:
Answer:
The answer is YZC, so the third option
Step-by-step explanation:
The explanation for this one is fairly simple, as the lines are already drawn out for you!
The line labeled C lines up with 152 on the protractor, and after connecting that to the base point Z in the middle and then the base line of Y, you get YZC
Hopefully I helped you!
Answer:
yzc
Step-by-step explanation:
i took the test and got it right