A mole or fraction of a mole represents a _______number of atoms or molecules.a. specific
b. nonspecific

Can I get some help matching these from the left to the right?

1) increased surface area concentration decreases around solute
2) like polarity increases rate rate proportional to K.E.
3) temperature matching solvent and solute
4) stirring finely divided solute

Answers

Answer 1

Answer: A mole or fraction of a mole represents a nonspecific number of atoms or molecules. The answer is letter A.

The correct answer is number 2, like polarity increases rate rate proportional to K.E.

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What is a lunar eclipse?

Answers

Moon eclipse is when the moon interposes between the sun and behind the Earth. The moon passes behind the Earth into its umbra and not viceversa! This is possible when the three of them are ALIGNED (in syzygy). In Romania, there was such eclipse that could be seen at an October night last year.

A lunar eclipse is basically when the earth passes between the moon and sun, causing the moon to appear darkened. Also, unlike the solar eclipse, the lunar eclipse occurs during the day.

A block initially at rest on a horizontal, frictionless surface is accelerated by a constant horizontal force of 5 newtons. if 15 joules of work is done on the bock by this force, the kinetic energy of the block increases by

Answers

Answer: The kinetic energy of the block increases by 15 Joules.

Explanation:

Work done is defined as the product of force and displacement of the object.

Mathematically,

$W=F.s$

where,

W =work done

F = force

s = Displacement

Kinetic energy is defined as the energy which is possessed by the virtue of object's motion.

In the question, it is given that work done on block is 15 Joules and we need to find the change in kinetic energy of the block.

We know that,

Work done on the object = Change in kinetic energy of the object

Thus, Kinetic energy is increased by 15 Joules.

The kinetic energy depends on the work done by the applied force. The kinetic energy of the block increases by 15 J.

What is kinetic energy?

The energy possessed by an object by its motion is known as the object's kinetic energy.

Given data-

The magnitude of the constant horizontal force is F = 5 N.

The work done on the block is, W = 15 J.

As per the work-energy theorem, the work done by the applied force is equal to the change in kinetic energy.

Then,

W = ΔKE

Solving as

15 = ΔKE

ΔKE = 15 J

Thus, we can conclude that the block's kinetic energy increases by 15 J.

Learn more about kinetic energy here:

brainly.com/question/999862

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!The shape of a projectile's trajectory is an ellipse.

True or false?

Answers

The statement is false. The shape of an object's trajectory can be a number of different shapes, not just an ellipse.

State the law of conservation of energy

Answers

Answer:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

The flywheel of a steam engine runs with a constant angular velocity of 140 rev/min. When steam is shut off, the friction of the bearings and of the air stops the wheel in 1.9 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? (b) How many revolutions does the wheel make before stopping? (c) At the instant the flywheel is turning at 70.0 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 40 cm from the axis of rotation? (d) What is the magnitude of the net linear acceleration of the particle in (c)?

Answers

Answer:

A) α = -1.228 rev/min²

B) 7980 revolutions

C) α_t = -8.57 x 10^(-4) m/s²

D) α = 21.5 m/s²

Explanation:

A) Using first equation of motion, we have;

ω = ω_o + αt

Where,

ω_o is initial angular velocity

α is angular acceleration

t is time the flywheel take to slow down to rest.

We are given, ω_o = 140 rev/min ; t = 1.9 hours = 1.9 x 60 seconds = 114 s ; ω = 0 rev/min

Thus,

0 = 140 + 114α

α = -140/114

α = -1.228 rev/min²

B) the number of revolutions would be given by the equation of motion;

S = (ω_o)t + (1/2)αt²

S = 140(114) - (1/2)(1.228)(114)²

S ≈ 7980 revolutions

C) we want to find tangential component of the velocity with r = 40cm = 0.4m

We will need to convert the angular acceleration to rad/s²

Thus,

α = -1.228 x (2π/60²) = - 0.0021433 rad/s²

Now, formula for tangential acceleration is;

α_t = α x r

α_t = - 0.0021433 x 0.4

α_t = -8.57 x 10^(-4) m/s²

D) we are told that the angular velocity is now 70 rev/min.

Let's convert it to rad/s;

ω = 70 x (2π/60) = 7.33 rad/s

So, radial angular acceleration is;

α_r = ω²r = 7.33² x 0.4

α_r = 21.49 m/s²

Thus, magnitude of total linear acceleration is;

α = √((α_t)² + (α_r)²)

α = √((-8.57 x 10^(-4))² + (21.49)²)

α = √461.82

α = 21.5 m/s²

A speedy rabbit is hopping to the right with a velocity of 4.0 \,\dfrac{\text m}{\text s}4.0 s m 4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when it sees a carrot in the distance. The rabbit speeds up to its maximum velocity of 13 \,\dfrac{\text m}{\text s}13 s m 13, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with a constant acceleration of 2.0 \,\dfrac{\text m}{\text s^2}2.0 s 2 m 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction rightward.

Answers

Answer: 38.25 m

Explanation:

In this situation we need to find the distance $d$ between the rabbit and the carrot, and we can use the following equation, since the rabbit's acceleration is constant: