Answer:
The percentage of its mechanical energy does the ball lose with each bounce is 23 %
Explanation:
Given data,
The tennis ball is released from the height, h = 4 m
After the third bounce it reaches height, h' = 183 cm
= 1.83 m
The total mechanical energy of the ball is equal to its maximum P.E
E = mgh
= 4 mg
At height h', the P.E becomes
E' = mgh'
= 1.83 mg
The percentage of change in energy the ball retains to its original energy,
ΔE % = 45 %
The ball retains only the 45% of its original energy after 3 bounces.
Therefore, the energy retains in each bounce is
∛ (0.45) = 0.77
The ball retains only the 77% of its original energy.
The energy lost to the floor is,
E = 100 - 77
= 23 %
Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %
Answer: 23
Explanation: gradpoint
Answer:
The work done to the block
See
Workdone is Force×Displacement .
Also work done is total mechanical energy of body
Mechanical energy=Kinetic energy
So option C is correct
Please and Thank you
When you rub your wool socks on a carpeted floor and then touch a metal doorknob, you get shocked. This happens due to the transfer of electrons from the carpet to the socks, resulting in a buildup of negative charge which is discharged when you touch the grounded doorknob.
When you vigorously rub your wool socks on a carpeted floor, you transfer electrons from the carpet to the socks through friction. This creates a buildup of negative charge on the socks. When you then touch a metal doorknob, which is grounded, the excess electrons on your socks quickly flow to the doorknob, resulting in a sudden discharge of static electricity and a shock.
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