the base of a regular pyramid is a hexagon whose perimeter is 84 feet. the volume of the pyramid is approximately 4,677.85 cubic feet. find the height of the pyramid.

Answers

Answer 1
Answer:

Answer:

The height of the pyramid is 27.56\ ft

Step-by-step explanation:

we know that

The volume of the pyramid is equal to

V=(1)/(3)BH

where

B is the area of the base of the pyramid

H is the height of the pyramid

step 1

Find the area B of the regular hexagonal base

we know that

The perimeter of a regular hexagon is

P=6b

where

b is the length side of the hexagon

we have

P=84\ ft

substitute

84=6b

solve for b

b=14\ ft

Remember that the area of a regular hexagon is the same that the area of six equilateral triangles

Determine the area of the six equilateral triangles, applying the formula of the law of sines

B=6[(1)/(2)b^2sin(60\°)]

substitute the value of b

B=6[(1)/(2)(14)^2sin(60\°)]

B=509.22\ ft^2

step 2

Find the height of the pyramid

V=(1)/(3)BH

we have

V=4,677.85\ ft^3

B=509.22\ ft^2

substitute

4,677.85=(1)/(3)(509.22)H

solve for H

14,033.55=(509.22)H

H=14,033.55/(509.22)H

H=27.56\ ft


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Answers

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Answers

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