PHYSICS HIGH SCHOOL

Two 0.006 Kg bullets are fired with speeds of 20.0 m/s and 50.0 m/s respectively. What are their kinetic energies? Which bullet has more kinetic energy? What is the difference of their kinetic energies?

Answers

Answer 1

Answer:

Answer:

a) Kinetic energies

K₁ = 1.2 J

K₂ = 7.5 J

b) The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s , K₂ = 7.5 J

c) K₂ -K₁ = 6.3 J

Explanation:

The kinetic energy (K) is that due to the movement of a body and is calculated as follows:

K = (1/2) m*v² (J)

Where :

m : the mass of the body ( kg)

v is the speed of the body (m/s)

Data

m₁ = m₂ = 0.006 Kg

v₁ = 20 m/s

v₂ = 50 m/s

a)Calculation of the kinetic energy

K₁ = (1/2) (m₁)*(v₁)²

K₁ = (1/2) (0.006)*(20)²

K₁ = 1.2 J

K₂= (1/2) (m₂)*(v₂)²

K₂ = (1/2) (0.006)*(50)²

K₂ = 7.5 J

b) K₂ ˃ K₁

The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s, K₂ = 7.5 J

c) Difference of their kinetic energies (K₂ -K₁)

K₂ -K₁ = 7.5 J - 1.2 J = 6,3 J

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answered|Score .8

Answers

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Calculate the man’s mass. (Use PE = m × g × h, where g = 9.8 N/kg.)A man climbs a wall that has a height of 8.4 meters and gains a potential energy of 4,620 joules. His mass is about
kilograms

Answers

Answer:

mass=56.12kg

Explanation:

PE=mgh

4620=m×9.8×8.4

make msubject of the formula...

m =4620/(9.8×8.4)

m=4620/82.32

m=56.12kg

a child riding a bicycle at 15 m/s decelerate at the rate of 3.0 meters per second squared for 4.0 seconds. what is the child's speed at the end of the 4.0 seconds?

Answers

3m/ $s^(2)$ of deceleration for 4 seconds.
3 x 4 = 12
15 - 12 = 3
The child will be riding a bicycle at 3m/s after 4 seconds.

If you want a full equation (which you might not):
let a be acceleration rate, Vf be final velocity, Vi as initial velocity, and t as time.
a = (Vf - Vi)/t
let's fill in everything we know now:

-3 = (Vf - 15)/4
now let's solve for Vf

-3 = Vf/4 - 15/4
-Vf/4 = 3 - 15/4
Vf/4 = -3 + 15/4
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Vf = 3

Therefore, final velocity is 3m/ $s^(2)$

When preparing for a rocket launch, the mission control center uses the phrase "T minus" before liftoff. ...T minus 3, T minus 2, T minus 1, ... After the rocket has launched, "T plus" is used while the rocket is in flight. ...T plus 1, T plus 2, T plus 3, ... When does the rocket launch? What does "T" represent?

Answers

The rocket launches when the countdown reaches "T minus 0." "T" represents the time remaining until a specific event.

What does "T" symbolize in rocket launch countdowns?

In the context of rocket launches, "T" represents time. The countdown begins with "T minus" indicating the time remaining until liftoff. As the countdown progresses, the value of "T" decreases, counting down to zero, which marks the exact moment of launch.

Once the rocket is airborne, the countdown transitions to "T plus," denoting the time elapsed since liftoff. This standardized countdown terminology allows mission control to communicate crucial timing information precisely and efficiently during various phases of the rocket's journey.

Answers

Answer:

a = 2 m/s²

Explanation:

Given: 20 g, 40N

To find: Acceleration (a)

Solution: To find the acceleration (A), divide the force by the weight

A = F ÷ m

= 40 ÷ 20

= 2 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

A pendulum is swinging back and forth with a period of 2.0 seconds here on Earth. This pendulum is then brought to the Moon, where the acceleration due to gravity is much smaller. What will happen to the period of the pendulum, assuming everything else about it (mass, length, initial swing height, etc) remains exactly the same? Explain your answer.