Answer:
There are 27,720 ways to select the committee
Step-by-step explanation:
First, it is necessary to know how many ways are there to select 3 members, if there are 9 members of the mathematics department. This can be found using the following equation:
Where nCk gives as the number of ways in which we can select k elements from a group of n elements. So, replacing n by 9 and k by 3 members, we get:
So, there are 84 ways to select 3 members from 9 members of the mathematics department.
At the same way, we can calculate that there are 330 ways to select 4 members from the 11 that belong to the Computer science department as:
Finally the total number of ways in which we can form a committee with 3 faculty members from mathematics and 4 from the computer science department is calculated as:
9C3 * 11C4 = 84 * 330 = 27,720
2. )10
3. ) –5
4.) 5
Can someone help please.
Answer:
Step-by-step explanation:
To solve the inequality, we want to isolate the variable .
Let's begin by adding 23 to both sides of the inequality:
This simplifies to:
Therefore, the solution to the inequality is .
#BTH1
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B.) the input (x) values of the relation
C.) a set of points that pair input values with output values
D.) x and y values written in the form (x,y)
Answer:
x = 3
Step-by-step explanation:
m<R = 180 - 110 = 70
m(arc)KQ = 2 × 70 = 140
m(arc)PQ = 140 - 50 = 90
30x = 90
x = 3
[3-(5-(7+1))^2]-5+3]
[3-(5-8)^2]-5+3]
[3-(-3)^2]-5+3]
[3+9]-5+3]
[12]-5+3]
12[-2]
12+2
14