Answer:
There will be no movement of kinesin motor protein along the microtubules .
Explanation:
Microtubules is an important component of cytoskeleton which play an important role in maintaining cell shape,cell motility,cell division regulation etc.
Whereas kinesin belongs to the family of motor proteins present in the eukaryotic cell.Kinesin plays an important role axonal transport.
The hydrolysis of ATP generates energy to power up the movement of kinesin along the microtubules.
According to the given question if kinesin and microtubules were incubated with an non hydrolyzable ATP analog instead of ATP,then the movement of kinesin along the microtubules will not occur due to lack of energy because the non-hydrolyzable analog of ATP cannot undergo hydrolysis to release energy.
B.There is an increase in the amount of oxygen being delivered to the muscle cells during the process of aerobic respiration.
C.There is an increase in the amount of glucose being produced in the muscle cells during the process of aerobic respiration.
D.There is an increase in the amount of lactic acid being produced in the muscle cells during the process of anaerobic respiration.
The reason the basketballplayer experiences this muscle soreness after a workout is there is an increase in the amount of lacticacid being produced in the muscle cells during the process of anaerobicrespiration. The correct option is D.
Muscle fatigue is characterized by a reduction in maximal force or energyproduction as a result of contractile activity.
It can start at various points along the motorpathway and therefore is typically classified into central and peripheral components.
Muscle fatigue is a sideeffect that makes it difficult to move normally. Some people feel a stingingsensation in their muscles.
They may also be tired all the time and lack the energy to perform daily tasks. Muscle fatigue is frequently caused by exercise.
The most crucial etiology of skeletalmuscle fatigue has been identified as intracellular acidosis caused primarily by lactic acid accumulation.
Thus, the correct option is D.
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Answer:D
Explanation:.........
Answer:
B. oxygen and picks up electrons
Answer:
Explanation:
Answer:
This question includes the following options to choose from:
A) 2 B) 12 C) 8 D) 9 E) 10
3 point testcrosses focus on analyzing the inheritance blueprints of alleles by crossing triple heterozygotes with triple recessive homozygotes, allowing therefore to find out the distance between the alleles, and also their location order on the chromosome.
And it all comes down to the frequency of recombination, in this case such frequency between C&A is 0.02, in the same fashion that it's 0.08 between A&B; thereby the answer is A). 2
Answer:
all cells come from other cells
Answer:
a. 81/256
b. 175/256
C. 1/4
D. 9/256
E. 54/256
Explanation:
Since both parents are heterozygous for galactosemia (Gg). The possibility of their children will be
GG Gg Gg gg. The probability for one child to be unaffected is 3/4 and affected is 1/4 since it is a recessive diseases:
A. Probability for none of the four children to be affected is 3/4*3/4*3/4*3/4=81/256
B.
Since the probability of unaffected children is 81/256
The probability that at least one child will be affected is 1-(3/4*3/4*3/4*3/4)=1-(81/256)
= 175/256
C. The probability that only one if the child will be affected is 1/4
D. The probability that the first two will have galactosemia and the second two will not is
1/4*1/4*3/4*3/4=9/256
E. The probability that two will have galactosemia and two will not, regardless of order.
Since the probability that two will have galactosemia and two will not is 9/256.
The total possible outcome that 2 among 4 children will be born regardless of order (first and second, first and third, first and fifth, second and third, second and fourth, third and fourth) is 6
Hence the probability two will have galactosemia and two will not, regardless of order is 9/256*6= 54/256