MATHEMATICS HIGH SCHOOL

Polygon ABCDEFGH will be dilated by a scale factor of 3.4 with the origin as the center of dilation to produce polygon A′B′C′D′E′F′G′H′. What will the length of A'H'¯¯¯¯¯¯¯ be?

Answers

Answer 1

Answer: A'H'¯¯¯¯¯¯¯=2*3.4 = 6.8

Answer 2

Answer:

Answer:

6.8 units

Step-by-step explanation:

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What is the coefficient of the variable in the expression 6 − 4x − 8 + 2?6
2
−4
−8

Answers

If you would like to find the coefficient of the variable in the expression 6 - 4x - 8 + 2, you can calculate this using the following step:

6 - 4x - 8 + 2 = 6 - 8 + 2 - 4x = - 4x

The correct result would be - 4.

Answer:

The coefficient is -4

Step-by-step explanation:

Find 25% less than 56

Answers

Answer:the answer is 31

Step-by-step explanation:

We are looking for a new number which is 25 less than 56.

We will get the new number by subtracting 25 from 56.

We write it down as:

56-25=31

And finally the solution for: What number is 25 less than 56?

is 31

A rotating light on top of a lighthouse sends outrays of light in opposite directions. As the beacon
rotates, the ray at an angle 8 makes a spot of light
that moves along the shore. The lighthouse is
located 500 m from the shoreline and makes
one complete rotation every 2 min.
Determine the equation that expresses the
distance, d, in metres, as a function
of time, t, in minutes.

Answers

Answer:

$\sf d = 500 \cdot (\theta(t))$

Step-by-step explanation:

The equation can be derived using the following trigonometric identity:

That is:

$\sf tan(\theta) =( opposite )/( adjacent)$

In this case, the opposite side is the distance from the lighthouse to the shoreline and the adjacent side is the distance from the lighthouse to the spot of light on the shoreline (500m)

The angle is equal to the angle of the light beam.

It is changeable according to the time. so,

$\sf \theta \textsf{ will be } \theta t$

Substituting these values into the trigonometric identity gives us the following equation:

$\sf tan(\theta t) = (d)/(500)$

Solving for d gives us the following equation:

$\sf d = 500 \cdot (\theta(t))$

Therefore, the equation to express the distance, d, in metres, as a function of time, t, in minutes is:

$\sf d = 500 \cdot (\theta(t))$

11. Una escuela telesecundaria tiene una pista de carreras que mide de kilómetro.Tres alumnas corrieron las siguientes distancias: Juanita: 1 vueltas, Esperanza
21 vueltas y Evelyn: 1650 m. ¿Cuántos metros corrieron Juanita y Esperanza?
¿Y cuántas vueltas dio Evelyn?

Answers

Answer:

Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.

Step-by-step explanation:

The complete question is: A telesecundaria school has a race track that measures one kilometer.

Three students ran the following distances Juanita: 1 laps, Esperanza 21 laps and Evelyn: 1650 m. How many meters did Juanita and Esperanza run? And how many laps did Evelyn make?

As we know that 1 meter = 0.0025 laps

So, the number of laps Evelyn make = 1650 $*$ 0.0025

= 4.125 laps

Also, 1 lap = $(1)/(0.0025)$ meters

1 lap = 400 meters

So, the meters that Juanita run = 1 $*$ 400 = 400 meters

Similarly, the meters that Esperanza run = 21 $*$ 400

= 8400 meters

Hence, Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.

Final answer:

Juanita ran 1 kilometer and Esperanza ran 21 kilometers. Evelyn ran 1 lap.

Explanation:

To find out how many meters Juanita and Esperanza ran, we need to add up their distances. Juanita ran 1 lap, which is equal to the length of the track. Since the track is 1 kilometer long, Juanita ran 1 kilometer. Esperanza ran 21 laps, so she ran 21 kilometers.

Evelyn ran 1650 meters. To find out how many laps Evelyn ran, we need to divide 1650 by the length of the track. Since the track is 1 kilometer long, Evelyn ran either 1 lap or 1.65 laps. However, we're told that Evelyn ran 1650 meters, so she ran 1 lap.

Learn more about Distances here:

brainly.com/question/33716087

#SPJ3

Simplify the expression below.
√169

Answers

Answer:

The simplified form of the given expression is 13.

Step-by-step explanation:

The given expression is

$√(169)$

It can be written as

$√(13* 13)$

$√(13^2)$

$(13^2)^{(1)/(2)}$ $[\because √(x)=x^{(1)/(2)}]$

$13^{(2)/(2)}$ $[\because (x^m)^n=x^(mn)]$

$13^(1)$

$13$

Therefore the simplified form of the given expression is 13.

The square root of 169 is 13 because 13X13 equals to 169.

Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).

Answers

Solving for the midpoint can be done by looking for the average of each of the given x-coordinates and y-coordinates. The 2 obtained averages are the new x-coordinate and y-coordinate. This shown below:

Midpoint = ( (-2 + 4)/2 , (5 + -9)/2 )
Midpoint = (1,-2)

Therefore, the new midpoint is (1,-2)

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