The correct option for above statement is:
B.Joseph Proust
Explanation:
Joseph Proust printed his Law of Definite Proportions (or Law of Constant Composition) in 1794. This law states that a compound consists of exact proportions of parts by mass no matter however the compound was created.
The substrate, enzyme pair from the citric acid cycle that is INCORRECT is E) Citrate, aconitase.
The citric acid cycle, also known as the Krebs cycle, is a crucial metabolic pathway for generating energy in cells. Each step involves specific substrates and enzymes. While all other options (A, B, C, and D) correctly match substrates and enzymes involved in the cycle, option E (Citrate, aconitase) is incorrect.
Aconitase is responsible for catalyzing the interconversion of citrate and isocitrate, not for the conversion of citrate itself. The correct pair for citrate is citrate synthase, which catalyzes the formation of citrate from oxaloacetate and acetyl-CoA.
Understanding these substrate-enzyme pairs is essential in comprehending the citric acid cycle's intricacies. Accurate knowledge of these reactions aids in grasping how cells produce energy through this pathway. This emphasizes the significance of precise knowledge of biochemical pathways for an accurate understanding of cellular processes.
In the context of cellular metabolism, identifying the correct enzyme for each substrate is vital for accurate biochemical analysis and the design of targeted interventions for metabolic disorders. Among the given options, the substrate, enzyme pair that is incorrect in the citric acid cycle is Citrate, aconitase.
To Know more about Enzyme, refer;
The incorrect substrate-enzyme pair from the citric acid cycle is Oxaloacetate, citrate synthase.
The citric acid cycle, also known as the Krebs cycle or tricarboxylic acid cycle, is a series of chemical reactions that occur in the mitochondria of cells. It plays a crucial role in the aerobic respiration process, generating energy-rich molecules such as ATP.
The citric acid cycle involves the oxidation of acetyl-CoA derived from carbohydrates, fats, and proteins. Each step of the cycle is catalyzed by a specific enzyme, which acts on a particular substrate.
The correct substrate-enzyme pairs in the citric acid cycle are as follows:
Therefore, the incorrect substrate-enzyme pair from the given options is D) Oxaloacetate, citrate synthase.
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1 mol = 6.022 x 10²³ atoms
In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.
So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃
But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃
Water has specific heat. This helps us with homeostasis.
Answer:
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
The equation for the ionization of the is given as:
Molar concentration =
By stoichiometry of the reaction:
1 mole of gives 1 mole of and 1 mole of
When the solubility of is S moles/liter, then the solubility of will be S moles\liter and solubility of will be S moles/liter.
Thus of the salt at is
(1) CH3OH (3) H2O
(2) C6H12O6 (4) KOH
Answer:
The answer is 4) KOH
Explanation:
Electrolytes are substances which ionize when dissolved in water. They are classified as:
Strong electrolyte: Which completely ionize when in water. Eg: NAOH, KOH (produces K+ and OH- ions when dissolved in water)
Weak electrolyte: partially ionize when in water. Eg: Acetic acid
Non-electrolyte: Do not ionize at all in water. Eg: Alcohols such CH3OH, sugars such as glucose (C6H12O6).
KOH is an electrolyte. Therefore, option (4) is correct.
Electricity flows via water-dissolved materials. Ions in a solution conduct electricity.The options:When dissolved in water, methanol (CH3OH) does not form ions.2. C6H12O6 (Glucose): It does not dissolve into ions in water, hence it is not an electrolyte.
Water doesn't dissolve into ions, hence it's not an electrolyte.4. Dissolved in water, potassium hydroxide (KOH) forms ions (K+ and OH-), making it an electrolyte. Therefore, KOH as an electrolyte is the correct option.
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