HELP NEEDED, GIVING BRAINLIEST!Apply the dilation D to the polygon with the given vertices. Name the coordinates of the image points. Identify and describe the transformation.


D: ( x, y ) ---> ( 4x, 4y )

A ( 2, 1 ), B ( 4, 1 ), C ( 4, -3 )


A. This is a dilation about (0, 0) with a scale factor of 0.25; A'(8, 4), B' (16, 4), C' (16, -12).


B. This is a dilation about (0, 0) with a scale factor of 4; A'(8, 4), B' (16, 4), C' (16, -12).


C. This is a dilation about (0, 0) with a scale factor of 0.25; A'(0.5, 0.25), B, (1, 0.25), C' (1, - 0.75).


D. This is a dilation about (0, 0) with a scale factor of 4; A'(0.5, 0.25), B'(1, 0.25), C'(1, -0.75)
HELP NEEDED, GIVING BRAINLIEST! Apply the dilation D to the - 1

Answers

Answer 1
Answer:

The correct answer is:

B. This is a dilation about (0, 0) with a scale factor of 4; A'(8, 4), B' (16, 4), C' (16, -12).

Step-by-step explanation:

Given

Dilation: D : (x,y) => (4x,4y)

And Vertices

A ( 2, 1 ), B ( 4, 1 ), C ( 4, -3 )

Applying dilation on all vertices

A ( 2, 1 ) => A'(4*2, 4*1) => A'(8,4)\nB ( 4, 1 ) = > B' (4*4 ,4*1) = > B'(16,4)\nC(4,-3) => C' (4*4 , 4*-3) => C'(16, -12)

To find the scale factor,

As we are multiplying each vertex coordinate by 4, the dilation factor is 4.

Moreover,

(A')/(A) = ((8,4))/((2,1)) = (4,4)

Hence the scale factor is 4.

So,

The correct answer is:

B. This is a dilation about (0, 0) with a scale factor of 4; A'(8, 4), B' (16, 4), C' (16, -12).

Keywords: Dilation, Scale factor

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Caleb had to share 3 1/4 boxes of supplies with his 12 classmates. What fraction of a box does each student receive?

Answers

Caleb had to share 3 1/4 boxes of supplies with his 12 classmates. So, the fraction of each student receives 13/48 of a box of supplies.

To find out what fraction of a box each student receives, we need to divide the total number of boxes (3 1/4 boxes) by the number of students (12 classmates).

Step 1: Convert 3 1/4 to an improper fraction.

3 1/4 = (4 × 3 + 1) / 4 = 13/4

Step 2: Divide the total number of boxes by the number of students.

Fraction of a box per student = (Total boxes) / (Number of students)

Fraction of a box per student = 13/4 ÷ 12

Step 3: To divide a fraction by a whole number, we multiply the fraction by the reciprocal of the whole number (flipping the fraction).

Fraction of a box per student = 13/4 × 1/12

Step 4: Simplify the fraction if possible.

Fraction of a box per student = 13/4 × 1/12 = 13/48

So, each student receives 13/48 of a box of supplies.

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What are some differences and similarities between a trapezoid and a square?

Answers

The difference between a square and a trapezoid is that first a square has equal sides while trapezoid does not have. The angles inside the square are perpendicular while trapezoid has not. A trapezoid also has one pair of non-parallel sides.
They both have 4 sides and 4 angles.
Trapezoid has 4 different length & angles, square has all same length and angles.

Simplify.7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54A) 11 square root of 6 end root minus 7 square root of 12
B) 11 square root of 3 end root minus 7 square root of 6
C) negative 3 square root of 9
D) 4 square root of 9

Answers

The simplest form of the expression ''7 square root of 3 end root minus 4 square root of 6 end root plus the square root of 48 end root minus the square root of 54'' would be, ''11 square root of 3 end root minus 7 square root of 6''. Hence, option B is true.

Used the concept of the square root of a number that states that,

The square root of a number is the number that, when multiplied by itself, gives the original number.

Given that the expression is,

7 square root of 3 end root minus 4 square root of 6 end root plus the square root of 48 end root minus the square root of 54.

Now, the mathematical form of the expression is,

7√(3) - 4√(6) + √(48) - √(54)

Simplify each term,

7√(3) - 4√(6) +4 √(3) - 3√(6)

Combine like terms,

7√(3) +4 √(3) - 4√(6) - 3√(6)

11√(3) - 7√(6)

It can be written as,

11 square root of 3 end root minus 7 square root of 6.

Hence, option B is true.

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7√(3)-4√(6)+√(48)-√(54)=7√(3)-4√(6)+√(16*3)-√(9*6)\n=7√(3)-4√(6)+4√(3)-3√(6)=11√(3)-7√(6)

Use the following frequency distribution to determine the midpoint of the second class.A. 17.0

B. 19.5

C. 16.5

D. 18.5

Answers

Class         Frequency    Mid-point
13-15           7            13+15/2=20.516-18           4            16+18/2=1719-21           3            19+21/2=2022-24           5            22+24/2=2325-27           7            25+27/2=2628-30           7            28+30/2=29

(16+18)/2 = 17
So, the answer is A (17).

What is the value of x in the equation 4x+8y=40 when y=0.8

Answers

inpus 0.8 for y
4x+8(0.8)=40
4x+6.4=40
minus 6.4 both sides
4x=33.6
divie both sides by 5
x=8.4

x=8.4 when y=0.8
4x+8y=40
4x + (8x.8)= 40
4x + 6.4 = 40 
4x = 33.6
x = 8.4

(2x-20)(5x+10)
help pls

Answers

Développement
10x + 20x -100x -200
=-70x -200