Find the sample space for tossing 2 coins. Then find P(exactly 1 head).A. 1/8
B. 1/2
C. 3/4
D. 1/4

Answers

Answer 1
Answer:

HH,HT,TT,TH
As evident from above sample space,the probability of finding exactly one Head 2\4 I.E 1\2
so the answer is B

Answer 2
Answer:

Option B. (1)/(2) is correct.

What is probability?

Possible chances of occurring an event are known as the probability of that event.

Sample space for tossing two coins is :

( {H,H} , {H,T} , {T,T} , {T,H} )

Formula used:

Probability of an event = (favourable)/(Total)

Exactly one head appeared 2 times i.e., {H,T} or {T,H}

Thus, Favourable outcomes = 2

Total outcomes = 4

P (Exactly one head) = (2)/(4) = (1)/(2)

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A six-foot person walks from the base of a broadcasting tower directly toward the tip of the shadow cast by the tower. When the person is 124 feet from the tower and 3 feet from the tip of the shadow, the person's shadow starts to appear beyond the tower's shadow. (a) Draw a right triangle that gives a visual representation of the problem. Label the known quantities of the triangle and use a variable to represent the height of the tower.

Solve this equation :

2/3q=18

Answers

The answer to your question is q = 27.

Least these in order from least to greatest 1.2, 02, 1.02, 1.002 ​

Answers

02, 1.2, 1.02, 1,002

Which choice is equivalent to the quotient shown here when x > 0?√50x^2 divide by √32x^2.

a.5√x/4
b.5x/4
c.√18x
d.√50x^3-32x^2

Answers

The quotient equivalent to the expression √(50x^3) / √(32x^2) is (5√x)/4.

Hence option B is the right choice.

How to find the quotient of an expression?

To find the quotient of an expression, we simplify the numerators and the denominators and then cancel off the like terms.

How to solve the question?

In the question, we are asked to find the equivalent expression to the quotient given by √(50x^3) / √(32x^2) .

To find the equivalentexpression, we need to simplify the given quotient as follows:

{√(50x³)}/{√(32x²)}

= {√(25.2.x².x)}/{√(16.2.x²)} [Since, 50x³ = 25.2.x².x, and 32x² = 16.2.x²]

= {√(5².2.x².x)}/{√(4².2.x²)} [Since, 25 = 5², and 16 = 4²]

= (5x.√2.√x)/(4x√2) [Since, √(ab) = √a√b, and √a² = a]

= (5√x)/4 [Cancelling the like terms √2 and x].

Thus, the equivalent expression is (5√x)/4.

Thus, the quotient equivalent to the expression √(50x^3) / √(32x^2) is (5√x)/4. Hence option B is the right choice.

The question provided is incomplete. The complete question is provided in the attachment.

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√(50x^2):√(32x^2)=\sqrt(50x^2)/(32x^2)=\sqrt{(25)/(16)}=(5)/(4)

Find the perimeter of a rectangular garden that has a width of 4x−6 and a length of 2x+4. im i n t e a r s pLEASE

Answers

The Perimeter: of the rectangular garden that has a width of 4x−6 and a length of 2x+4 is 2(2x - 7) + 2(3*2 + 4x).

What is perimeter?

Perimeter is the sum of length of the sides used to made the given figure.

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

WE need to find the perimeter of a rectangular garden that has a width of 4x−6 and a length of 2x+4.

Area = (2x - 7) * (3*2 + 4x)

Area = (2x - 7) * (6 + 4x)

Area =  8x - 42

The Perimeter: of the rectangular garden that has a width of 4x−6 and a length of 2x+4 is 2(2x - 7) + 2(3*2 + 4x).

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Answer:

Perimeter: 2(2x - 7) + 2(3*2 + 4x)

Step-by-step explanation:

Area: (2x - 7) * (3*2 + 4x)

         (2x - 7) * (6 + 4x)

                 8x-42

Perimeter: 2(2x - 7) + 2(3*2 + 4x)

X = -3 + 5y - 6 for y

Answers

Answer:

y = 1/5x + 9/5.

Step-by-step explanation:

x = -3 + 5y - 6

5y - 3 - 6 = x

5y - 9  = x

5y = x + 9

y = 1/5x + 9/5.

Hope this helps!

For the function f(x) = -2(x + 3)^2 -1, identify the vertex, domain, and range. A.) The vertex is (3, -1), the domain is all real numbers, and the range is y ≥ -1. B.) The vertex is (3, -1), the domain is all real numbers, and the range is y ≤ -1. C.) The vertex is (-3, -1), the domain is all real numbers, and the range is y ≤ -1. D.) The vertex is (-3, -1), the domain is all real numbers, and the range is y ≥ -1

Answers

ok so domain is all allowed numbers look at deonomenator and don't allow any numbers that will make it zero none that means domain=all real numbers vertex in form y=a(x-h)^2+k (h,k)=vertex we have y=-2(x+3)^2-1 h=-3 k=-1 vertex=(-3,-1) range the vertex opens down so max is y=-1 y≤-1 domain is all real vertex is (-3,-1) y≤-1 C