Answer:
C. number of protons in an atom's nucleus.
Explanation:
Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.
However, when we talk about the atomic number of the ion, it is not equal to the number of electrons as electron can be gained or loosed.
This is why, more appropriately, the number of the protons which are present in the nucleus of the atom is called the atomic number.
For example, Sodium has 11 protons in its nucleus which suggest that the atomic number of sodium is 11.
Answer:
The molecule of that compound.
Explanation:
By breaking a carbon double bond and adding chlorine.
By removing hydrogen because of chlorine’s attraction to hydrogen’s nucleus.
Chlorine and ethene do not react spontaneously.
Answer: option B m
Explanation:
It is an example for Electrophilic Addition of Halogen. And addition of Cl2 to Alkene is always Trans Addition. That means both cl atoms should add opposite side of double bond and results vicinal 1,2-dichloroethane as a product.
CH2=CH2 + Cl2-------> ClCH2CH2Cl
3. Explain the meaning of each term in the symbol
(AZ)X
a set of quantum numbers for the last electron in the atom
a configuration with numbers, letters, and superscripts
a dot structure of the atom
an orbital notation of the atom
Answer:
D. an orbital notation of the atom
Explanation:
Orbital notiation uses lines and arrows to show shells, subshells, and orbitals for electrons in an atom. Since it shows arrows being paired up in this diagram it would be the best model for Chuck to use.
On Edgenuity2020, the answer is D) an orbital notation of the atom
The charges of ions that Sulfur (S), Potassium (K), Boron (B), Iodine (I), and Bromine (Br) are most likely to form are -2, +1, +3, -1, and -1, respectively. This is determined by their positions on the periodic table.
The charge of an ion that a certain atom is most likely to form is dependent on its position on the periodic table. Elements on the left side of the periodic table (like potassium) tend to lose electrons and form positive ions, while elements on the right side (like sulfur, iodine, bromine) tend to gain electrons and form negative ions.
The charge of a sulfur (S) ion is usually -2 because sulfur, being in Group 16, tends to gain two electrons to reach a stable electronic configuration. The charge of a potassium (K) ion is usually +1. This is because potassium, which is in Group 1, usually loses one electron to achieve a stable electron configuration. The charge of a boron (B) ion is usually +3 because boron, being in Group 13, tends to lose three electrons in order to reach stability. The charge of an iodine (I) ion is usually -1 because iodine, which is in Group 17, tends to gain one electron to reach stability. Lastly, the charge of a bromine (Br) ion is usually -1, because bromine, also in Group 17, tends to gain one electron to attain a stable electronic configuration.
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Answer:
Sulfur (S) is
-2
Potassium (K) is +1
Boron (B) is +3
Iodine (I) is -1
Bromine (Br) is -1
Explanation: