b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom.
c. The hydrogen atoms of a water molecule have a partial negative charge.
d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule.
e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule.
f. The oxygen atom of a water molecule has a partial positive charge.
g The oxygen atom of a water molecule has a partial negative charge.
Answer:
The answer to your question is below
Explanation:
a. The hydrogen atoms of a water molecule have a partial positive charge. True.
b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom. True
c. The hydrogen atoms of a water molecule have a partial negative charge. False
d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule. True
e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule. False,
f. The oxygen atom of a water molecule has a partial positive charge. True
g The oxygen atom of a water molecule has a partial negative charge. True
B. +2
C. +3
D. +4
Answer: The correct answer is Option C.
Explanation:
Oxidation state is the number which is assigned to an element when it gains or looses electrons. If the element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.
We take the oxidation state of iron atom be 'x'.
Oxidation state of oxygen atom = -2
Evaluating the oxidation state of iron atom in :
Hence, the correct answer is Option C.
Answer:
shortest wavelength - gamma rays
highest wavelength - radio waves
Explanation:
Look at the electromagnetic spectrum
Answer:
I don't use your question?
Answer:
-1215.9J is the work done
Explanation:
It is possible to find work done in the change of volume of a gas at constant pressure using:
W = -P×ΔV
Where W is work, P is pressure and V is change in volume}
Replacing:
W = -6atm×(5L-3L)
W = -12atmL
As 1atmL = 101,325J, work done in joules is:
-12atmL ×(101.325J / atmL) = -1215.9J is the work done
The value of work done when a volume increases from 3 liters to 5 liters at 6 atm of pressure is -1215.9 Joules.
Workdone on any boby or by the body will be calculated as:
W = -P×ΔV, where
W = workdone
P = applied or exerted pressure = 6 atm
ΔV = change in volume due to workdone = (5-3) L
Negative sign in the formula shows that work is done on the opposite side of the pressure or volume.
On putting all these values on the above equation, we get
W = -6atm × (5L-3L)
W = -12 atmL
We know that, 1 atmL = 101,325 J,
So, workdone in joules will be written as:
-12 atmL × (101.325J / atmL) = -1215.9 J
Hence, -1215.9 J is the workdone.
To know more about workdone, visit the below link:
brainly.com/question/18363506
H2S
HSO4
H2SO4
H2SO3
The correct answer is H2SO3 I took the assignment already
The quantity of nitrogen the cylinder contains is 4477.8 g
Pressure is a force exerted in a perpendicular direction in any item.
By ideal gas law
PV = nRT
w = mass
Volume is 20.0 l
Pressure is
The molar mass of nitrogen is 28 g/mol
R is gas constant = 0.0821
Temperature is 28 converted into kelvin that is 301 k
Putting the values
Thus, the mass of nitrogen is 4477.8 g.
Learn more about pressure, here:
Answer : The mass of gas is, 4477.8 g
Solution :
using ideal gas equation,
where,
n = number of moles of gas
w = mass of gas
P = pressure of the gas =
conversion :
T = temperature of the gas =
M = molar mass of gas = 28 g/mole
R = gas constant = 0.0821 Latm/moleK
V = volume of gas = 20 L
Now put all the given values in the above equation, we get the mass of gas.
Therefore, the mass of gas is, 4477.8 g