The equation which can be used to determine the minimum and maximum optimal angles of launch is:
|x – 45| = 3
and the minimum angle that is still optimal is:
42 degrees.
Let x be the optimal angle by which the balloon is launched.
Also, it is given that the they launch the balloon at an angle within 3 degrees of 45 degrees.
i.e. the range at which the angle is launched lie between 3 degree less than 45 degree and 3 degree more than 45 degree.
Hence, the equation that will represent this relationship is:
|x-45|=3
Hence, on solving for the maximum value we have:
and the smallest optimal angle is given by:
3x^2-7x-2
doesn't factor
You can not factor this
I hope that's help !
Solve for q
Answer:
3(q-7)=27
3q-21=27
3q=48
q=16
Step-by-step explanation:
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Answer:
q = 16
Step-by-step explanation:
3(q - 7) = 27
3q - 21 = 27 | +21
3q = 48 | :3
q = 16