An object having a net charge of 28.0 µC is placed in a uniform electric field of 660 N/C that is directed vertically. What is the mass of this object if it "floats" in the field?(Hint: If an object "floats" consider what this means for the sum of the forces acting on it.)

Answers

Answer 1

Answer:

Answer:

The mass of this object is $\mathbf{1.71*10^(-3)\,kg}$

Explanation:

If an object floats, it means by Newton’s second law that the sum of the forces acting on it are equal to zero because it’s at rest, as you can see on the figure below, the only two forces acting on the charged particle are the weight (W) and the electric force (Fe) due the electric field (E), so Newton’s second law in this case is:

$\sum\overrightarrow{F_(y)}=0$

$F_(e)-W=0$

$W=F_(e)$ (1)

But weight is mass (m) times gravity acceleration (g) and the magnitude of the electric force is the product of the external electric field (E) and the charge of the particle (q), so using that on (1) and solving for m:

$mg=qE$

$m=(qE)/(g)=((28.0*10^(-6))(600))/(9.8)\approx\mathbf{1.71*10^(-3)\,kg}$

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Answers

In order foran object to accelerate, a force must be applied. It follows Newton’s secondlaw of motion where it states that a body at rest remains at rest unless aforce is acted upon it. When you move an object, you are exerting a force ontoit. By exerting a force on the object, you are actually displacing it from itsinitial position. You cannot apply force to the object without altering itsposition. Keep in mind that when you exert work, you are exerting energy too.

What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?

Answers

Answer:

The new length is 1.20138 m

Explanation:

1- We get the increase in length:

The old length = 1.2 m

The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.

The old temperature is 15°C.

The new temperature is 65°C

The increase in length= old length * coefficient of expansion *change in temperature

The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)

The increase in length = 0.00138 m

2- getting the new length:

new length = old length + increase in length

new length = 1.2 + 0.00138

new length = 1.20138 m

Hope this helps :)

1.201386 meters at 65 degrees C.
Will be your answer!

Hope I Helped!

A 4 watt night light is left on for 8 hours each night how much work does it do per night

Answers

1 watt = 1 joule per second

   (4 joules/second) x (3600 second/hour) x (8 hour)

   = (4 x 3600 x 8) (joule)

   = 115,200 joules .

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Answers

Answer:

Crest to the lowest point on the wave trough

Explanation:

The amplitude of the wave is the height of wave as measured from the highest point on the wave that is known as peak or crest to the lowest point on the wave known as trough. Wave length refers to the length of wave from one peak to another but amplitude or height can be determine by measuring the distance from its crest to its trough.

Final answer:

The amplitude of a wave is the maximum distance, or 'height', from the equilibrium position to the crest (highest point) or trough (lowest point) of the wave. This represents maximum displacement of the wave from its rest position.

Explanation:

The amplitude of a wave refers to the distance from the equilibrium or midpoint of the wave (the rest position) to the highest point of the wave known as the crest, or to the lowest point known as the trough. For instance, considering a wave on a graph representing a sound wave, the crest would be the highest peak on the graph and the trough would be the lowest point. We can visually represent this extent as height, but it's actually a measurement of maximum displacement of the wave from equilibrium (rest position). For physical waves, such as sound or light waves, a larger amplitude leads to a louder sound or a brighter light.

Learn more about Amplitude of a Wave here:

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Suppose you are standing in front of a concave spherical mirror. Which of the following image properties are possible? Your image is upright.Your image is inverted.

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Your image is real.

Your image is virtual.

All of the above.

Answers

Answer:

All are correct

Explanation:

A concave spherical mirror produces both types of images real and virtual of an object.

The concave spherical mirror forms a real image when the object placed between the focus and infinity.

The concave spherical mirror forms a virtual image when the object is placed between focus and the pole of the mirror.

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All the options are correct.

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Answers

Answer:

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