The line integral is
We have
so the integral reduces to
The line integral ∫C ysin(z) ds over the circular helix C, parametrized by x = cos(t), y = sin(t), z = t for 0 ≤ t ≤ 2π, evaluates to π√2.
To evaluate the line integral ∫C ysin(z) ds over the circular helix C given by x = cos(t), y = sin(t), z = t for 0 ≤ t ≤ 2π, we follow these steps:
1. Parameterize the curve: C is already parameterized as x = cos(t), y = sin(t), z = t.
2. Find the differential ds: ds = √(dx² + dy² + dz²) = √(sin²(t) + cos²(t) + 1)dt = √(1 + 1)dt = √2 dt.
3. Evaluate the integral: ∫C ysin(z) ds = ∫[0, 2π] sin(t) * sin(t) * √2 dt = ∫[0, 2π] sin²(t) * √2 dt.
Now, we'll integrate sin²(t) * √2 with respect to t:
∫ sin²(t) * √2 dt = (1/2) * ∫ (1 - cos(2t)) * √2 dt.
Using the power rule for integration, we get:
(1/2) * [(t - (1/2) * sin(2t)) * √2] | [0, 2π].
Plugging in the limits:
(1/2) * [(2π - (1/2) * sin(4π) - (0 - (1/2) * sin(0))) * √2].
Since sin(4π) = sin(0) = 0:
(1/2) * [(2π - 0 - 0) * √2] = π√2.
So, ∫C ysin(z) ds = π√2.
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15/25 Divididing numerator and denominator by 5 we get:
3 / 5
For questions 6-8, determine the number of solutions.
Type your answers as one, none, or many (no capital letters)
6
4(x + 5) - 2 = 18 + 4x
Answer:
Show a photo
Step-by-step explanation:
we can't see what you're talking about
Answer:
11 4/9
Step-by-step explanation:
ANDDD the answer is
A The line segments are parallel, and the image is twice the length of the given line segment.
B. The line segments are parallel, and the image is one-half of the length of the given line segment.
C. The line segments are perpendicular, and the image is twice the length of the given line segment.
DD The line segments are perpendicular, and the image is one-half of the length of the given line segment.
9514 1404 393
Answer:
A The line segments are parallel, and the image is twice the length of the given line segment.
Step-by-step explanation:
Dilation by a factor of 2 means any measure of the image is 2 times the corresponding measure of the original.
Dilation does not change any orientations, so the image will have the same orientation with respect to the origin, axes, or any other line segments. That means the dilated segment is parallel to the original. (If the center of dilation is on the original line segment, the dilated segment will overlay the original segment. That is specifically not the case here.)