2X^2-5x+2=0
Quadratic formula

Answers

Answer 1
Answer:

Answer:

The solutions are x_(1)=2\ and\ x_(2)=0.5.

Step-by-step explanation:

Given:

2x^(2) -5x+2=0

Now, to solve by using quadratic formula:

x=\frac{-b\pm \sqrt{b^(2)-4ac}}{2a}

Here a=2,b=-5\ and\ c=2

x=\frac{-(-5)\pm \sqrt{(-5)^(2)-4* 2* 2}}{2* 2}

Now, here we will take eitherx=(-(-5)+√(25-16))/(4)and thenx=(-(-5)-√(25-16))/(4).

x=(-(-5)+√(25-16))/(4)        x=(-(-5)-√(25-16))/(4)

x=(5+√(9))/(4)               x=(5-√(9))/(4)

x=(5+3)/(4)                         x=(5-3)/(4)

x=(8)/(4)                               x=(2)/(4)

x_(1)=2                                  x_(2)=(1)/(2)=0.5

Therefore, the solutions are x_(1)=2\ and\ x_(2)=0.5.


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Which function represents g(x), a reflection of f(x) = (3)x across the y-axis?g(x) = 2(3)x
g(x) = −(3)x
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g(x) = 2(3)−

Answers

Answer: g(x)=(3)^(-x)

Step-by-step explanation:

We know that if a figure is reflected across y axis then its y coordinate remains same but the x coordinate changes its polarity.

i.e. the function f(x) will become f(-x) .

Now, the given function :f(x)=(3)^x

Then , after reflection across y axis the new function will become:

g(x)=f(-x)=(3)^(-x)

Consider the function represented by the equation x – y = 3. What is the equation written in function notation, with x as the independent variable?

Answers

We have an equation and we want to rewrite it as a function. The function will be: y = f(x) = -3 + x

So we start with the equation:

x - y = 3

And we want to write this in the form y = f(x) (because we want x to be the independent variable)

To do this, we just need to isolate y on one side of the equation.

x - y = 3

Now we subtract x in both sides:

x - y - x = 3 - x

-y = 3 - x

Now we multiply both sides by -1:

-1*(-y) = -1*(3 - x)

y = -3 + x

Then we have:

y = f(x) = -3 + x

This is the equation written in function notation.

If you want to learn more, you can read:

brainly.com/question/3139036

When the question asks to write the equation "in function notation, with x as the independent variable?", it simply is asking for the isolation of y. This means that y must be on its own side of the = sign with everything else on the other, because the dependent variable is being affected by the independent variable (hence the name "dependent").

The first step is to subtract x from both sides, so you end up with -y=3-x. This may look finished, but y is still attached to a negative sign. To fix this, we must divide both sides by -1 to receive our final answer of y=-3+x, which, when rearranged to be written in proper notation, reads as:

y=x-3

Hope I could help! :)

An equation in slope-intercept form of the line that passes throughthe given point and is perpendicular to the given line. (-3,1); y = 1/3x + 2*

Answers

Answer:

y=1/3x squared +2x+4

Step-by-step explanation:

shania wants to measure the capacity of her bathroom sink. Circle the unit of measurement she should use to measure its capacity. POUNDS. TONS. QUARTS. OUNCES

Answers

quarts since the other 2 measure weight

-Hope this helps :)

Answer:

Quarts

Step-by-step explanation:

The other options measure weight

What is 30% of x is 60

Answers

30% ×  = 60

30% = (30)/(`00) = 0.3

0.3x = 60

Divide by 0.3 on either sides to isolate x

(0.3x)/(0.3)(60)/(0.3)
x = 200

30% of 200 is 60

All chalk line is place around the perimeter of the football field. What is the length of this line in feet? The field is 531/3yd length and 120yd width

Answers

Answer: 1040 feet.

Step-by-step explanation:

We know that , Perimeter of a rectangle = 2 (length +width)

As per given , we have

Length of football ground = 53(1)/(3)\text{yards}=(53*3+1)/(3)\text{yards}=(160)/(3)\text{ yards}

Width = 120 yards

Since, the football ground is rectangle in shape.

Then , Perimeter of the ground =2((160)/(3)+120) yards

=2((160+3(120))/(3)) yards

=2((160+360)/(3))yards

=2((520)/(3)) yards

=(1040)/(3) yards

Also, 1 yard =3 feet

i.e. Perimeter = (1040)/(3)*3=1040  feet

Hence, the required perimeter is


346 2/3 feet is the length of the line around the perimeter of the field