MATHEMATICS COLLEGE

At a large department store, the average number of years of employment for a cashier is 5.7 with a standard deviation of 1.8 years, and the distribution is approximately normal. If an employee is picked at random, what is the probability that the employee has worked at the store for over 10 years? 99.2% 0.8% 49.2% 1.7%

Answers

Answer 1

Answer:

Answer:

option 0.8%

Step-by-step explanation:

Data provided in the question:

Mean = 5.7 years

Standard deviation, s = 1.8 years

Now,

P(the employee has worked at the store for over 10 years)

= P(X > 10 years)

= $P (Z > (X-Mean)/(\sigma))$

= $P (Z > (10-5.7)/(1.8))$

= P (Z > 2.389 )

= 0.008447 [from standard z table]

= 0.008447 × 100% = 0.84% ≈ 0.8%

Hence,

the correct answer is option 0.8%

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Answers

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Step-by-step explanation:Let's solve for x.

−x+3y=9

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Answers

Answer:

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Step-by-step explanation:

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Answers

Solution1:-

Statement : corresponding angles in similar triangles must be congruent .

Answer : True

Solution2:-

Statement : The hypotenuse of a right angle triangle has to be opposite of 90 degree .

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Answers

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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