Write the quadratic equation in general form and then choose the value of "b."(2x - 1)(x + 6) = 0

Answers

Answer 1
Answer: first of all to transfer (2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.

(2x - 1)(x + 6) = 0
 becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - 6

now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - 6

a=2,b=11,and c=-6

Answer 2
Answer:

Answer:

The answer is b=11

Step-by-step explanation:

You are welcome.


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What is the value of b that will make the system of equations consistent when x = 2?8x + 3y = 14
bx + 2y = 6

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