A triangle is considered equilateral has

Answers

Answer 1
Answer: 3 equal sides and 3 equal angles
Answer 2
Answer: equilateral triangle means : a triangle with all 3 sides = in length

Related Questions

Evan will spend $835.90 for new carpeting. He has $765.00 in the account linked to his debit card. The bank charges $5 penalty fee, per day, for using his debit card to make purchase if he doesn't have enough funds in his account. What will he pay altogether if he chooses to use his debit card and doesn't put any more money in his account for 3 days?
Please help me please please
Rearrange the equation so b is the independent variable..a – 7 = 3(b +2)a =
How to find the area of a circle ?
The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how many centimeters long is the smaller leg  please explain how you got it 

What's the answer for this ​

Answers

Answer:

nub

Step-by-step explanation:

lol

A person drove at 24 miles per hour for 4 hours, then at 20 miles per hour for 2 hours. How far did the person drive in all?

Answers

the person traveled 136 miles
24+20=44
20+20=40÷4=44

The following comparative stem-and-leaf plot represents the ages (in years) of the members of two professional basketball teams. Which of the following statements is correct?A. The youngest player is on Team A, and the oldest player is on Team B.
B. The youngest player is on Team A, and the oldest player is on Team A.
C. The youngest player is on Team B, and the oldest player is on Team A.
D. The youngest player is on Team B, and the oldest player is on Team B.

Answers

Team A              Team B
        8 9 | 1 | 9
  0 0 5 9 | 2 | 2 8 8 9
  1 2 4 4 | 3 | 0 0 4 5 8 9
        0 1 | 4 | 0

Ages of Team A: 18, 19, 20, 20, 25, 29, 31, 32, 34, 34, 40, 41
Ages of Team B: 19, 22, 28, 28, 29, 30, 30, 34, 35, 38, 39, 40

The youngest player is 18 = Team A
The oldest player is 41 = Team A

B. The youngest player is on Team A, and the oldest player is on Team A.

Answer:

D.the youngest player is on team B and the oldest player is on team A

Step-by-step explanation:

apexs

How many positive integers less than 25 can be formed by using the digits 1,2 and 3

Answers

I tried to think of a fancy formula for it, then decided it's just easier to list them:

1
2
3
11
12
13
21
22
23

That's 9 of them.
there are 9 numbers that are positive integers that can be formed by the #s 1,2,&3 THAT R LESS THAN 25 1 2 3 11 12 13 21 22 23

If triangle RST is congruant to triangle ABC, the measure of angle A equals x^2-8x, and the measure of angle C equals 4x-5, and the measure of angle R equals 5x+30 find the measure of angle C [ only an algebraic solution can receive full credit.]

Answers

In any statement like this one: \triangle RST \cong \triangle ABC you can assume that the points match up in the order that you are given them.
This means that \angle A \cong \angle R.
We know that m\angle A = x^2-8x and m\angle R=5x+30, and because they are congruent we can set the two equal to each other.

x^2-8x=5x+30
Let's get everything to one side.
x^2-13x-30=0
Let's solve by factoring, since it's easy to do with these whole numbers.
We're looking for two number thats add to -30 and multiply to -13...
These would be -15 and 2.
Since our leading coefficient (_x²) is 1, we can factor straight to (x-15)(x+2).
Here's what it would look like if you went through all the steps anyways, though.
x^2-15x+2x-30=0
x(x-15)+2(x-15)=0
(x+2)(x-15)=0
Any value which causes either factor to equal 0 is a solution.
(The second factor wouldn't matter b/c 0 times anything is still 0)
Therefore x = -2 or 15.
Only one of these is possible, however!
If you use x = -2, you will find that the angle measure 4x-5 is negative, which is impossible. In this case, x must be 15.

Let's find the measure of angle C.
m\angle C=4x-5\ where\ x=15\nm\angle C=4(15)-5\nm\angle C=60-5\n\boxed{m\angle C = 55\°}
             ΔRST ≡ ΔABC
      
           <R = <A
       (5x + 30)° = (x² - 8x)°
          5x + 30 = x² - 8x
  -x² + 5x + 30 = x² - x² - 8x
  -x² + 5x + 30 = -8x
      + 8x           + 8x
-x² + 13x + 30 = 0
x = -(13) ± √((13)² - 4(-1)(30))
                       2(-1)
x = -13 ± √(169 + 120)
                    -2
x = -13 ± √(289)
             -2
x = -13 ± 17
           -2
x = -13 + 17    U    x = -13 - 17
           -2                           -2
x = 4    U    x = -30
     -2                 -2
x = -2         x = 25

<C = 4x - 5       U    <C = 4x - 5
<C = 4(-2) - 5    U    <C = 4(25) - 5
<C = -8 - 5        U    <C = 100 - 5
<C = -13°          U    <C = 95°

or

          ΔRST ≡ ΔABC
      <A + <C = <R
     (x² - 8x)°+ (4x - 5)° = (5x + 30)°
       (x² - 8x) + (4x - 5) = (5x + 30)
         (x² - 8x + 4x - 5) = (5x + 30)
                   x² - 4x - 5 = 5x + 30
                      - 5x       - 5x        
                   x² - 9x - 5 = 30
                             - 30 - 30
                 x² - 9x - 35 = 0
x = -(-9) ± √((-9)² - 4(1)(-35))
                       2(1)
x = 9 ± √(81 + 140)
                  2
x = 9 ± √(221)
              2
x = 9 ± 14.86
              2
x = 9 + 14.86   U    x = 9 - 14.86
             2                            2
x = 23.86    U    x = -4.14
         2                        2
x = 11.93    U    x = -2.07

What's the answer for this question.

Answers

You're looking for a point that is not in the region where both functions touch (darker shade).

Points A, B, and D all fall into that region (even though you can't see it in the graph for D).

Your answer is C.