A computer simulation tossed a 10-faced die 5 times. How many possible outcomes exist?

Answers

Answer 1
Answer:

Answer:  There exists 100000 possible outcomes.

Step-by-step explanation:  Given that a computer simulation tossed a 10-faced die 5 times.

We are to find the number of possible outcomes that exists.

Since there are 10 faces of the die, so we have 10 possible options for each of the 5 tosses.

Therefore, the total number of possible outcomes is

n=10*10*10*10*10=10^5=100000.

Thus, there exists 100000 possible outcomes.

Answer 2
Answer: 10^5 1,000,000  believer or 100,000 didnt have a cal

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P=3a+2b2
Make a the subject of the formula

Answers

subtract 3a from both sides (will look like -3a+P=2b2) then subtract P (-3a=2b2-P) then divide both sides by -3

Determine if the rates $24 for 6 hours of work and $36 for 8 hours of work are equivalent. Explain your reasoning

Answers

No, because
24÷6= 4
36 ÷ 8 = 4.5

What is the area of a triangle with vertices at (0, −2), ​(8, −2)​ , and ​(9, 1)​ ?

Answers

Answer:

A=1/2*(8)*(3)

A=12

Description:

The area of a triangle is A=1/2*b*h

Meaning the area of the triangle is 12.

A=1/2*(8)*(3)

A=12

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Hope this helps.

Which ratios form a proportion? Option a) 3:9 Option b) 1223:1/2 Option c) 1/4:Done Option d) 9:16

Answers

Answer:

1223.3 is the ans oooo ooo oooo oooo ooo oooo

A manufacturer makes ball bearings out of molten steel. It takes 5.24 cubic centimeters of molten steel to make ? ball bearings that each have a diameter of 1 centimeter.

Answers

So we want to know how much ball bearings can be made with 5.24 cm^3 if one ball bearing has a diameter of 1 cm. We know that radius r=d/2=0.5cm So the volume V of one ball bearing is: V=(4/3)*pi*r^3 so V=(4/3)*3.14*(0.5)^3cm^3=0.524cm^3. Now we simply divide the volume of steel by the volume of the ball bearing: 5.24/0.524=10. So we can make 10 ball bearings from 5.24 cm^3 of steel

Answer: 10 ball bearings

Plato is annoying

Step-by-step explanation:

The area of the garden is 851 square meters. If the length of the garden is 23 meter, what is the width of the garden?

Answers

A=LW
so 851=23W
Divide both sides by  23 to get the width by itself and you get
37=W or the width is 37 meters