b. The cations in the salt bridge will migrate to the anode half-cell
c. The cathode will gain mass
d. The anode will lose mass
e. Reduction will occur at the cathode
Explanation:
Fats
The gallbladder stores bile ( made in the liver) which is secreted into the digestive tract to aid in the digestion of dietary fats.
B) the same type of atom.
C) many different compounds.
D) the same type of compound.
It is a hope it helps
Answer:
sodium
Explanation:
The three factors can affect gas pressure are temperature, its volume, and the number of its particles.
The force exerted by gaseous molecules as they collide with the walls of their container is referred to as gas pressure. If the volume and temperature of a gas container remain constant, increasing the number of gas particles causes an increase in pressure, and vice versa.
Automobiles have tires. These tires (or tyres in British English) must have air pressure. Inflatable beds and baloons are two additional examples.
The pressure rises as the number of gas particles in a container increases. The pressure increases as the volume of a container increases.
Thus, The enclosed gas's pressure is determined by the number of gas particles, the volume of the container, and the temperature of the gas.
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Answer:
Temperature, pressure, volume, and the amount of gas.
Explanation: I hope this helped you, have a blessed day in Jesus' name. Check out my Y t channel, it's called Going Dauntless
Answer:
1.74845
Explanation:
We have the following reaction:
I2 + H2 => 2 HI
Now, the constant Kc, has the following formula:
Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b
In this case I2 is A, H2 is B and C is HI
We know that the values are:
H2 = 1 × 10 ^ -3 at 448 ° C
I2 = 2 × 10 ^ -3 at 448 ° C
HI = 1.87 × 10 ^ -3 at 448 ° C
Replacing:
Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}
Kc = 1.87 ^ 2/2 * 1
Kc = 1.74845
Which means that at 448 ° C, Kc is equal to 1.74845
Answer:
Explanation:
[H2] = 10^-3
[I2] = 2*10^-3
[HI] = 0
in equilbiirum
[H2] = 10^-3 - x
[I2] = 2*10^-3 -x
[HI] = 0 + 2x
and we know
[HI] = 0 + 2x = 1.87*10^-3
x = ( 1.87*10^-3)/2 = 0.000935
then
[H2] = 10^-3 - 0.000935 = 0.000065
[I2] = 2*10^-3 -0.000935 = 0.001065
H₂ + I ⇄ 2 HI
Initially 1 × 10⁻³ 2 × 10⁻³
Change -9.35 × 10⁻⁴ -9.35 × 10⁻⁴ +1.87 × 10⁻³
At equil 6.5 × 10⁻⁵ 1.06 5 × 10⁻³ 1.87 × 10⁻³
HI increase by 1.87 × 10⁻³M