MATHEMATICS HIGH SCHOOL

Round 97.081 to the nearest tenth.

A : 97
B : 97.1
C : 97.8
D : 97.08

Answers

Answer 1
Answer: B 97.1
---------------
Answer 2
Answer:

Answer:

b

Step-by-step explanation:

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50) State the equation of a line that is perpendicular to 4x – 2y = 12 and passes through the point (-4,-3).
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Answers

Answer:

x+2y=-8

Step-by-step explanation:

Slope of given line = 2

Slope of the perpendicular line = -1/2

Equation of perpendicular line is (y-y1)=m(x-x1)

y-(-3)=-1/2(x-(-4))

y+3=-1/2(x+4)

2y+6=-x-2

x+2y=-8

F(x)=x^2+1;g(x)= x-3
Help me find (f•g)(x)

Answers

(f\cdot g)(x)=f(x)\cdot g(x)\n(f\cdot g)(x)=(x^2+1)(x-3)=x^3-3x^2+x-3

Y=2x+1 find the slope and y-intercept

Answers

The\ slope-intercept\ form:y=mx+b\n\nm\ is\ the\ slope\nb\ is\ y-intercept\n=========================\ny=2x+1\n\nthe\ slope:m=2\n\ny-intercept:b=1
y = mx + b 

y=2x+1 

Slope = 2 
Y-Intercept = 1 

What is ( √2 - √3 )² =

Answers

just use FOIL (First, Outer, Inner, Last).

( √2 - √3 ) X ( √2 - √3 )

First: √2 X √2 = 2
Outer: √2 X -√3 = -√6
Inner: -√3 X √2 = -√6
Last: -√3 X -√3 = 3

and then add them together.

2 - √6 - √6 + 3
5 - 2(√6)

The answer is 5 - 2(√6) . 

2-2(square root of 6)+ 3
=5-2(square root of 6)
or 0.1

Can you please take a look at these 3 problems?1. A carpentry shop makes dinner tables and coffee tables. Each week the shop must complete at least 9 dinner tables and 13 coffee tables to be shippeed to furniture stores. The shop can produce at most 30 dinner tables and coffee tables combined each week. If the shop sells dinner tables for $120 and coffee tables for $150, how many of each item should be produced for a maximum weekly income? What is the maximum weekly income?

Answers

Shop has to produced 30 furnitures.
It must be at least 9 dinner tables for 120$ and 13 coffe tables for 150$.
We noticed that income will be greater when shop will produce as much is possible coffe tables.
So if sum of furnitures is 30, shop should produce 9 (minimum) of dinner tables and the rest of cofee tables. 
There are 9 dinner tables and 30-9=21 coffe tables.
Income is equal:
120*9+21*150=4230$

How to solve number 21 :/

Answers

\left(\begin{array}{cc}1&1\n-2&1\end{array}\right) \bold{M}= 2\left(\begin{array}{cc}1&0\n0&1\end{array}\right)\n \bold{M}=2\frac{ \left(\begin{array}{cc}1&0\n0&1\end{array}\right) }{ \left(\begin{array}{cc}1&1\n-2&1\end{array}\right)}\n \bold{M}=2\left(\begin{array}{cc}1&0\n0&1\end{array}\right) \left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)

\left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)=(1)/(1-(-2))\left(\begin{array}{cc}1&-1\n2&1\end{array}\right)\n\left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)=(1)/(3)\left(\begin{array}{cc}1&-1\n2&1\end{array}\right)\n\left(\begin{array}{cc}1&1\n-2&1\end{array}\right)^(-1)=\left(\begin{array}{cc}(1)/(3)&-(1)/(3)\n(2)/(3)&(1)/(3)\end{array}\right)\n\n
\bold{M}= 2\left(\begin{array}{cc}1&0\n0&1\end{array}\right)\left(\begin{array}{cc}(1)/(3)&-(1)/(3)\n(2)/(3)&(1)/(3)\end{array}\right)\n\bold{M}= 2\left(\begin{array}{cc}(1)/(3)&-(1)/(3)\n(2)/(3)&(1)/(3)\end{array}\right)\n\bold{M}= \left(\begin{array}{cc}(2)/(3)&-(2)/(3)\n(4)/(3)&(2)/(3)\end{array}\right)
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