MATHEMATICS HIGH SCHOOL

Two angles that can be trisected with a straightedge and compass are a 90angle and a _____ angle.A. 9
B. 75
C. 45
D. 90

Answers

Answer 1
Answer: The correct answer is:

C) 45.

Explanation:

An angle of measure (2\pi)/(N) can be trisected if and only if N is not divisible by 3.

A 45° angle in radians is (\pi)/(4). Setting up a proportion, we can find the value of N to determine if this fits:

(\pi)/(4)=(2\pi)/(N)

Cross multiply:

\pi * N = 4 * 2\pi \n N\pi = 8\pi
 
This means N = 8, and is not divisible by 3; thus the 45 degree angle is trisectible.
Answer 2
Answer:

the answer on apex is 45°

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Given a test statistic of t=2.315 of a left tailed test with n=8

Answers

Answer:

Null hypothesis: \mu =110

Alternative hypothesis:\mu \neq 110

The sample size on this case is n=8, then the degrees of freedom are given by:

df = n-1= 8-1=7

The statistic is given by:

t= (\bar X -\mu)/((s)/(√(n)))

For this case the value of the statistic is given t = 2.315

Since we are using a bilateral test the p value would be given by:

p_v = 2*P(t_(7)>2.315) =0.054

And we can use the following excel code to find it:

"=2*(1-T.DIST(2.315;7;TRUE))"

Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:

0.05<P-value <0.10, fail to reject the null hypothesis

Step-by-step explanation:

Assuming this complete question :"Given a test statistic of t=2.315 of a left-tailed test with n=8, use a 0.05 significance level to test a claim that the mean of a given population is equal to 110.

Find the range of values for the P-value and state the initial conclusion 1 point) 0.05<P-value <0.10; reject the null hypothesis

0.05<P-value <0.10, fail to reject the null hypothesis

0.025 < P-value <0.05; reject the null hypothesis

0.025< P-value<0.05; fail to reject the null hypothesis"

For this case they want to test if the population mean is 110 or no, the systemof hypothesis are:

Null hypothesis: \mu =110

Alternative hypothesis:\mu \neq 110

The sample size on this case is n=8, then the degrees of freedom are given by:

df = n-1= 8-1=7

The statistic is given by:

t= (\bar X -\mu)/((s)/(√(n)))

For this case the value of the statistic is given t = 2.315

Since we are using a bilateral test the p value would be given by:

p_v = 2*P(t_(7)>2.315) =0.054

And we can use the following excel code to find it:

"=2*(1-T.DIST(2.315;7;TRUE))"

Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:

0.05<P-value <0.10, fail to reject the null hypothesis

I REALLY NEED HELP WITH THIS I HAVE NO CLUE WHAT IM DOING PLEASE HELP!!!!!!!!!!!!! F(x)=9x^3+2x^2-5x+4 and g(x)=5x^3-7x+4. what is f(x)-g(x)? show all of your steps and write your final answer in factored form

Answers

f(x)=9x³+2x²-5x+4
g(x)=5x³-7x+4

f(x)-g(x)=(9x³+2x²-5x+4)-(5x³-7x+4)=
=9x³+2x²-5x+4-5x³+7x-4=
=(9x³-5x³)+2x²+(-5x+7x)-4=
=4x³+2x²+2x-4

Answer; f(x)-g(x)=4x³+2x²+2x-4

Solve. 8/x + 15/x^2 = -1A.
x= 5,-3

B.
x= -5,-3

C.
x= -5,3

D.
x=5,3

Answers

8/x + 15/x^2 = -1
(8x+15)/x^2 = -1
8x + 15 = -1*x^2
8x + 15 = -x^2
x^2 + 8x + 15 = 0
(x+5)(x+3) = 0
x+5=0   ................     x+3=0
x = -5  .....................  x = -3

saludos :)

What’s the potential difference across a 5.0 resistor that carries a current of 5.0A

Answers

Answer:

25

Step-by-step explanation:

Potential difference

make use of the formula:

V = IR

where :

v--- potential difference

I ---- current

R --- resistance

place the values into the formula

V = 5 * 5

= 25

The potential difference is 25

How many lines of symmetry does the hexagon have?

Answers

Look\ at\ the\ picture\n\nAnswer:6

Solve the absolute value equation. 

|x| = –15

Answers

|x|=-15\ \ FALSE\ x\in\O\n\nbecause\ |x|\geq0\ for\ every\ x\in\mathbb{R}.
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