B) exothermic
C) reversible
D) irreversible
Answer: B) exothermic
Explanation:
Endothermic: The chemical reactions in which reactants form products by absorption of energy are called as endothermic reactions.
Exothermic : The chemical reactions in which reactants form products along with release of energy are called as exothermic reactions. Thus if walls turn hot that means the energy has been released.
Reversible: The chemical reactions in which reactants form products and products can also be converted back to reactants are called as reversible reactions.
Irreversible: The chemical reactions in which reactants form products but products can not be converted back to reactants are called as irreversible reactions.
(2) Chlorine molecules have strong covalent bonds.
(3) Chlorine molecules have weak intermolecular forces of attraction.
(4) Chlorine molecules have strong intermolecular forces of attraction.
6.11
4.94
5.65 - this one is correct
Answer:
5.65 is the pH.
Explanation:
I am assuming that you are asking for confirmation on your answer. The answer is 5.65.
You would do:
[pOH] = -log[OH-]
= -log[4.5*10^-9]
equals about 8.3468
To find pH your would subtract the pOH from 14.
14-8.3468 = 5.65 << Rounded to match the answer choices.
When a barium atom loses two electrons it becomes a positive ion and its radius decreases. Barium (Ba) has atomic number 56 so it has 2 electrons in first shell of an atom to become stable according to duplet rule. Then other 52 electrons revolve in the shells according to octet rules.
Another 2 electrons are in the outermost shell. To become stable electrons lose to form barium ions (Ba+2). Hence, by losing 2 electrons the outermost shell will be diminished so its radius decreases and by losing electrons it becomes positive ions.
Answer:
The correct answer is option 3, It becomes a positive ion and its radius decreases
Explanation:
As per the Octet rule, Barium has 2 electrons in its outermost shell. When it loses the two electron it gains two positive charge i.e Ba2+. As the barium loses the two electron from its outermost shell, the outermost shell becomes vacant and thus is no more considered as a part of atomic geometry of the barium atom and since the outermost shell is considered negligible the radius of barium atom reduces automatically.