The answer would be furnace.
Answer:
the correct answer is furnace
Answer:
1.1 x 10⁵m/s²
Explanation:
Given parameters:
Velocity = 452m/s
distance = 0.93m
Unknown:
Acceleration of the bullet = ?
Solution:
To solve this problem, we use one of the kinematics equation which is given below:
V² = U² + 2aS
V is the final velocity
U is the initial velocity = 0m/s
a is the unknown acceleration
S is the distance traveled
So;
452² = 0² + (2 x a x 0.93)
204304 = 1.86a
a = 1.1 x 10⁵m/s²
The acceleration of the bullet in the gun barrel can be calculated using the kinematic equation for motion. By substituying the given values into the equation, we find the acceleration to be approximately 1.095 x 10^5 m/s^2.
The subject of this question is Physics, specifically a topic under mechanics known as kinematics. The problem given can be solved using kinematic equations which are used to describe the motion of an object without considering the forces that cause it to move. In this case, the final velocity (vf) of the bullet is given as 452 m/s, the initial velocity (vi) is assumed to be 0 as it starts from rest, and the distance (d) is given as 0.93 m. We are asked to determine the value of acceleration (a).
Using the kinematic equation vf2 = vi2 + 2ad and substituting the given values, we get (452 m/s)2 = 0 + 2*a*0.93 m. We can rearrange to solve for acceleration to get: a = (452 m/s)2 / (2*0.93 m) = 109523.66 m/s2.
So, the acceleration of the bullet in the gun barrel is approximately 1.095 x 105 m/s2.
#SPJ3
Answer:
it is a simple machine
Explanation:
Let's assume that the coordinate system is defined as positive in the first quadrant.
The system has its origin in the place where Ingrid kicks the football ball.
We have then that the horizontal component is given by:
Rewriting we have:
Rounding the obtained result we have:
Answer:
The horizontal component of the initial velocity to the nearest tenth is:
is correct answer => 8.5 m/s
Answer:
By the information given, I am not sure how the event has played out. However, using common knowledge, I can give a scenario of how it may play out.
When removing the first block (the foundation), gravity will pull the other blocks down, as the strength of gravity exceeds that of the strength of air holding it up. This means that all the blocks on top would fall.
By definition of Newton's 1st - 3rd laws, the blocks would not move unless a force is given to it (i.e., removing the bottom block, which causes gravity). Gravity would pull the other blocks downwards. This would lead to the falling of the stack of blocks.
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Answer:
Explanation:
A stack of blocks sits in equilibrium. That means, by Newton's 1st law, all blocks will remain stationary. The weight of each block is balanced by the reaction force from the block underneath it. The bottom block experiences a reaction force equals to the total weight of all blocks from the ground.
When the bottom block is removed, there will not be any reaction force from the ground. That causes a disturbance in the equilibrium. Without the balancing reaction, the blocks will have the gravity force from their weights pulling them down. By Newton 2nd law, the unbalance force will cause the blocks to accelerate towards the ground until they all crash-land.