What is the correct formula for calculating pH?

Answers

Answer 1

Answer: PH = - log [ H⁺ ] for POH = - log [ OH⁻]

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A buffering solution consists of both strong acids and bases.
a. True
b. False

Answers

False. A buffering solution consists of a WEAK acid such as CH3COOH, C5H5N, or ammonia. A buffering solution resists pH change upon the addition of an acidic or basic components. It can neutralize little amounts of added acid or base, thus maintaining the pH of the solution relatively stable. The correct answer is letter "B. false"

What is c2h5oh and the difference between it and c2h6o

Answers

-Physical condition: C₂H₅OH is liquid; CH₃OCH₃ is a gas.
-Reactivity: C₂H₅ reacts with sodium (Na) metallic, releasing H₂ and forming the sodium ethoxide, Na (+) C₂H₅-O (-) (C₂H₅ONa).CH₃OCH₃ no reacts with sodium.-water solubility: C₂H₅OH dissolves in any proportionCH₃OCH₃ is poorly soluble in H₂O.
-polarity: C₂H₅OH is very polar, form hydrogen bonds.CH₃OCH₃ is little polar, doesn't have H available to form hydrogen bridge.
Write C₂H₆O may cause ambiguity because there are 2 different substances with this formula:-ethyl alcohol or ethanol = CH₃---CH₂---H
methyl ether = CH₃---O---CH₃

If you label a bottle only with C₂H₆O, will be very difficult to know if the compound is methyl ether or ethanol, which can be very dangerous in the laboratory. As only the ethanol C₂H₅OH is structured, it is convenient to use preferably this formula. For the methyl ether, it is more efficient to use the formula CH₃OCH₃.

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What volume of a 5.0% (v/v) Acetic Acid solution will contain 40.mL of Acetic Acid?

Answers

5.0% ( V/V) :

5.0 mL ------------- 100 mL ( solution )
40 mL --------------- ? ( solution )

V = 40 . 100 / 5.0

V = 4000 / 5.0

V = 800 mL

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In a laboratory, a student makes a solution by completely dissolving 80.0 grams of KNO3(s) in 100.0 grams of hot water. The resulting solution has a temperature of 60.°C. The room temperature in the laboratory is 22°C.Classify, in terms of saturation, the type of solution made by the student.

Answers

Answer:

Unsaturated solution.

Explanation:

At 60°C, 100.0g of water can dissolve 110g of KNO₃.

By definition, if you add 110g of KNO₃, the solution will be saturated, if you add more than 110g, the solution becomes supersaturated (That means crystals of solute will form), if you add less than 110g, the solution is unsaturated.

In the problem, you are adding 80g of KNO₃(s), that means you made a unsaturated solution.

Answer: Unsaturated

Explanation: There are three types of saturation levels that can be chosen, unsaturated, saturated, and supersaturated. If you look on Table G on the Reference Table, find the temperature in which the solution is at and go up until you reach the amount of dissolved substance (grams). If the dot is over the line then it is supersaturated, if its on the line then its saturated, and if it's below the line then is unsaturated.
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What is the difference between a crystalline material and an amorphous material? Give an example of each type.

Answers

Answer :

As we know that there are two types of solids.

(1) Amorphous Solids

(2) Crystalline Solids

Amorphous Solids : It is a type of solids in which the constituent particles of the matter are arranged in the random manner.

That means there is no proper arrangement of atoms in solid lattice but the atoms or molecules are closely spaced that means they can move freely from one place to another.

The examples of amorphous solid are, plastics, glass, rubber, metallic glass, polymers, gel, fused silica, pitch tar, thin film lubricants, wax.

Crystalline Solids : It is a type of solids where the constituent particles of the matter are arranged in the specific manner.

That means there is a proper arrangement of atoms in solid lattice. They do not have space between the molecules or atoms and they can not move freely from one place to another.

The examples of crystalline solids are, quartz, calcite, sugar, mica, diamonds, snowflakes, rock, calcium fluoride, silicon dioxide, alum.

Given the balanced equation representing a reaction at 101.3 kPa and 298 K:N2(g) + 3H2(g) => 2NH3(g) + 91.8 kJ
Which statement is true about this reaction?
(1) It is exothermic and DH equals -91.8 kJ.
(2) It is exothermic and DH equals +91.8 kJ.
(3) It is endothermic and DH equals -91.8 kJ.
(4) It is endothermic and DH equals +91.8 kJ.

Answers

Answer (4)

Endothermic processes: are those in which occurs the absorption of heat.
the change of enthalpy (ΔH) is greater than zero.

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