6 and 7
7 and 8
8 and 9
The least possible pairof integers are 7 and 8.
And the inequality is x + y ≥ 14. The correct option is C.
In mathematics, "inequality" refers to a relationship between two expressions or values that are not equal to each other. To solve the inequality, you may multiply or divide each side by the same positive number, add the same amount to each side, take the same amount away from each side, and more. You must flip the inequality sign if you multiply or divide either side by a negative number.
Given:
The sum of two consecutive integers is at least 14.
Let x and y be the two consecutive integers.
So, x + y ≥ 14.
1). When x = 5 and y = 6,
Then,
5 + 6 ≥ 14.
11 ≥ 14.
This is contradiction.
2). When x = 6 and y = 7,
Then,
7 + 6 ≥ 14.
13 ≥ 14.
This is contradiction.
3). When x = 7 and y = 8,
Then,
7 + 8 ≥ 14.
15 ≥ 14.
15 > 14
This is the required integers.
4). When x = 8 and y = 9,
Then,
8 + 9 ≥ 14.
17 ≥ 14.
17 > 14
The above statement holds the required inequality.
Here, we want the least possible pair of integers.
Therefore, 7 and 8 are the required pairs.
To learn more about the inequality;
#SPJ3
Answer: 7 and 8
Step-by-step explanation: As the sum is at least 14, the integers are 7 and 8 by the fact that the numbers are consecutive.
Answer:
x=3, y =2
(3,2)
Step-by-step explanation:
y =2/3 x
y = -2/3 x +4
set them equal to each other y=y
2/3 x = -2/3 x + 4
add 2/3 x to each side
2/3 x+2/3x = -2/3x + 2/3 x + 4
4/3 x = 4
multiply by 3/4 on each side to clear the fraction
3/4 * 4/3 x = 3/4 * 4
x = 3
now we need to find y
y = 2/3 x
y = 2/3 * 3
y =2
420 in2
B.
140 in2
C.
144 in2
D.
288 in2