Answer:
Step-by-step explanation:
Consider the function for the domain .
Find , where f^(-1) is the inverse of f.
Also state the domain of f^(-1) in interval notation.
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We can start solving this problem by finding the inverse of f(x). This is done by switching the x- and y- variables, and solving for y.
We can start solving for y by subtracting 3 from both sides of the equation.
Get rid of the radical by squaring both sides of the equation.
Use FOIL to multiply the binomial (x-3) together.
Combine like terms.
Subtract 4 from both sides of the equation.
Divide both sides of the equation by -1.
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The domain and range of a function are flipped for its inverse, meaning that to find the domain of the inverse function, you can find the range of the original function f(x), and that will be your inverse function's domain.
The range of is , since the vertical shift of the graph is at k = 3. You can also graph this function on a calculator to see that the graph does indeed start at y = 3.
Now that we know the domain and range of the original function, we know that these are flipped for the inverse function.
Original function:
Inverse function:
The final answer is:
The inverse .
You can also write the domain as: .
Answer:
12 chickens and 11 pigs
Step-by-step explanation:
We know that...
Chickens have 2 feet and 1 tail.
Pigs have 4 feet and 1 tail.
Let c represent chickens.
Let p represent pigs.
We need to create two equations. One for feet, and one for tails.
Tails:
Because each animal has 1 tail, we can say that the number of pigs, (p) plus the number of chickens, (c) must equal 23. So...
c + p = 23
Feet:
Because each chicken has two feet, and each pig has 4 feet, we can say that 2 times the number of chickens, (c) plus 4 times the number of pigs, (p) needs to equal 68. So...
2c + 4p = 68
Now we have two equations.
2c + 4p = 68
and
c + p = 23
We can use the substitution method to find c and p. The substitution method involves solving for one of the variables with one of the equations, then placing it into the other equation, so that you only have one variable to solve for, which you can do with simple algebra.
Solve for c
c + p = 23
c = 23 - p
Add that to the other equation.
2c + 4p = 68
2(23 - p) + 4p = 68
Solve for p
46 - 2p + 4p = 68
46 + 2p = 68
2p = 22
p = 11
Now that we know p, we can plug that into one of the equations to find c.
c + p = 23
c + (11) = 23
c = 12
Now we have c and p.
There are 12 chickens and 11 pigs on the farm.