b. moving faster.
c. slowing down.
d. at rest.
How would NGC 3603 be classified?
O A. As a galaxy
O B. As a nebula
O C. As a planet
D. As a solar system
Answer:
A. NGC 3603 would be classified as Nebula
Explanation:
If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then the traveler's total displacement would be 51.30 kilometers.
An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
As given in the problem If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then we have to find the traveler's total displacement,
the total displacement in the east direction = 18.6 + 30.3Cos45°
the total displacement in the east direction = 40 km
the total displacement in the south direction = 10.7 + 30.3Cos45°
the total displacement in the south direction = 32.12 km
The net resultant displacement = √(40² + 32.12²)
The net resultant displacement = 51.30 kilometers
Thus, the traveler's total displacement comes out to be 51.30 kilometers.
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We can determine the speed of an object with only a tape measure and a stopwatch first by measuring the distance traveled by any given body and simultaneously measuring the time taken to cover this distance with the help of the stopwatch
The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
speed = total distance /Total time
Suppose a body travels a total distance of 750 meters in a total time of 75 seconds, we can measure this distance with the help of a tape measure and the time with the help of a stopwatch its speed would be 4 meters/seconds
speed = distance measured by tape measure /stopwatch time
= 750/75
= 10 m/s
Thus, we can determine the speed of an object with only a tape measure and a stopwatch
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