Given the following mAB = mBC= mCD in circle F what is the measure of angle AFB
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Find least common multiplier of 4x,8 is 8x
Multiply by LCM = 8x
1/4 x * 8 x + 3 * 8 x = 2 x * 8 x - 5/8 * 8 x
Refine:
2 + 24 = 16 x² - 5 x
Subtract 16 x² - 5 x from both sides:
2 + 24 x - ( 16 x² -5 x) = 16 x² - 5 x - (16 x²-5 x)
Refine: - 16 x² - 29 x + 2 = 0
Solving with the quadratic formula :
for a = - 16 , b = 29 and c = 2
x1 = - 29 √ 29² - 4(-16)*2
-----------------------------
2 (-16)
x1 = - √ 969 - 29
---------------------
32
x2 = - 29 - √ 29² -4(-16)*2
-----------------------------
2(-16)
x2 = √ 969 + 29
---------------------
32
The final solutions to the quadratic equation are:
x1 = - √ 969 - 29
-------------------
32
x2 = √ 969 + 29
-------------------
32
hope this helps!
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Answer
49.67mph
Step-by-step explanation:
Data: 53 miles
1 hour 4 minutes.
Convert 4 minutes to hours:
4/60 = .067
Add like terms (hours)
1+ 0.067= 1.067
mph = m/h
mph = 53/1.067 = 49.67mph
The average speed of the car will be 49.67mph.
What is speed?
The speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance. The speed is a scalar quantity and does not require any direction to represent it.
Given that Chloe drives from her house to her grandma's house 53 miles away in an hour and 4 minutes. The speed will be calculated by using the formula below:-
Distance traveled = 53 miles
Time = 1 hour 4 minutes.
Convert 4 minutes to hours:
4/60 = .067
Add like terms (hours)
1+ 0.067= 1.067
Now the speed will be:-
Speed = Distance / Time
Speed = 53 / 1.067
Speed = 49.67 mph
Therefore, the average speed of the car will be 49.67mph.
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y - 3 = -x² - 2x + 3 - 3
y - 3 = -x² - 2x
y - 3 - 1 = -x² - 2x - 1
y - 4 = -(x²) - (2x) - (1)
y - 4 = -(x² + 2x + 1)
y - 4 = -(x² + x + x + 1)
y - 4 = -(x(x) + x(1) + 1(x) + 1(1))
y - 4 = -(x(x + 1) + 1(x + 1))
y - 4 = -(x + 1)(x + 1)
y - 4 = -(x + 1)²
y - 4 + 4 = -(x + 1)² + 4
y = -(x + 1)² + 4
Equation B: 2y = 3 – 4z
Step 1: –2(y) = –2(15 – 2z) [Equation A is multiplied by –2.]
2y = 3 – 4z [Equation B]
Step 2: –2y = 15 – 2z [Equation A in Step 1 is simplified.]
2y = 3 – 4z [Equation B]
Step 3: 0 = 18 – 6z [Equations in Step 2 are added.]
Step 4: 6z = 18
Step 5: z = 3
In which step did the student first make an error?
Step1
Step 2
Step 3
Step 4
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Because the student divided only the right side by 2. If you divide one side by a number you have to do the same with the other side to maintain the equality.
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1
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