7a-3=3-2a
I don't know how to solve this question

Answers

Answer 1

Answer: 7a-3=3-2a
9a-3=3 (add 2a to both sides)
9a=6 (add 3 to both sides)
a=6/9 (divide by 9 to both sides)

Answer 2

Answer: get all variables (in this case, "a") on one side by adding "2a" to both. this cancels the "-2a". then, combine like terms. also move "-3" to the other side, by adding "3". finally, divide the "6" and "a" by "9" to get variable alone. therefore, "a = 2/3".
7a-3=3-2a
+2a +2a
9a-3=3
+3 +3
9a=6
a=2/3

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$9X^2-12X+4=0$ X=?

Answers

$9x^2-12x+4=0$

$(3x)^2-2\cdot 2\cdot3x+2^2=0$

$(3x-2)^2=0, but...(3x-2)^2 \geq 0$ , ∨ x∈R

$So, (3x-2)^2=0$

$3x-2=0$ ⇒ $3x=2$ ⇒ $\boxed { x= (2)/(3) }$

$9x^2-12x+4=0\n(3x-2)^2=0\n3x-2=0\n3x=2\nx=(2)/(3)$

Y = 4(2)
(x + 2)2 + (y - 3)2 = 16

Answers

Answer:

1/4545

Step-by-step explanation:

suppose y varies directly with x, and y=8 when x=-6. What direction variation equation relates x and y? What is the value of y when x=-2

Answers

B. y = –1.33x; 2.67

(3x - 40)° (2x + 23)°

Answers

Answer:

Step-by-step explanation:

The expression (3x - 40)° (2x + 23)° represents the product of two angles, (3x - 40)° and (2x + 23)

(3x - 40)° (2x + 23)° = (3x - 40)(2x + 23)°

3x - 40)(2x + 23)° = 3x(2x + 23) - 40(2x + 23)°

3x(2x + 23) - 40(2x + 23)° = 6x² + 69x - 80x - 920

6x² + 69x - 80x - 920 = 6x² - 11x - 920

simplified expression of (3x - 40)° (2x + 23)° is 6x² - 11x - 920.

The sum of two numbers is 19, and their difference is 55. What are the two numbers?

Answers

Answer:

37 and -18

Step-by-step explanation:

Let one number be x and other y

1 x + 1 y = 19 .............1

1 x -1 y = 55 .............2

Eliminate y

multiply (1)by 1

Multiply (2) by 1

1 x 1 y = 19

1 x + -1 y = 55

Add the two equations

2 x = 74

/ 2

x = 37

plug value of x in (1)

1 x + 1 y = 19

37 + 1 y = 19

1 y = 19 -37

1 y = -18

y = -18

37 and -18

Final answer:

The two numbers, which sum to 19 and have a difference of 55, are 37 and -18.

Explanation:

The sum and difference of two numbers can provide the solution to the problem. In this case, the sum of the two numbers is 19 and the difference is 55. To solve this, we start by setting up two equations based on the problem: x + y = 19 and x - y = 55.

Then we solve these equations simultaneously. We can add the two equations together to eliminate 'y'. This gives us 2x = 74, or x = 37. Substituting x = 37 into the first equation, we get 37 + y = 19, which gives y = -18.

So, the two numbers are 37 and -18.

Learn more about Solving Simultaneous Equations

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Suppose a triangle has sides 3, 4, and 6. Which of the following must be true? A. The triangle in question is a right triangle. B. The triangle in question is not a right triangle. C. The triangle in question may or may not be a right triangle.

Answers

We can use the Pythagorean theorem:
c² = a² + b²
In this case:
6² = 3² + 4²
36 = 9 + 16
36 = 25 ( not correct )
This is not a right triangle.
Answer:
B ) The triangle in questionis not a right triangle.

Answer:

not a right triangle

Step-by-step explanation:

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