The function is a parabola, and the problem asks to transform the equation into f(t)=a(x-h)2 + k
Given f(t) = 4t2 -8t +7
= (4t2 - 8t + 4) + 7 - 4
=4 (t2 - 2t + 1) + 3
= 4 (t-1) 2 +3
This removes C and D from the viable choices.
Differentiating the f(t),
f’(t) = 8t – 8, the maximum/minimum value occurs at f’(t) = 0
0 = 8t – 8
t = 1
determining if maximum or minimum, f”(t) > 0 if minimum, f”(t) < 0 maximum
f”(t) = 8 > 0, therefore minimum
f(1) =4(1)^2 – 8(1) +7
= 3
Therefore, minimum height is 3.
Answer:
T= 4 s (second option).
Answer:
Step-by-step explanation:
we know that
If two lines are perpendicular
then
the product of their slopes is equal to minus one
so
In this problem line AB and line PQ are perpendicular
Step 1
Find the slope of the line AB
The equation of the line AB is
isolate the variable y
------>
The slope of the line AB is equal to
Step 2
Find the slope of the line PQ
remember that
we have
----> slope line AB
so
substitute and solve for m2
Step 3
Find the equation of the line PQ
The equation of the line into point-slope form is equal to
we have
substitute
-----> multiply by both sides
-----> divide by both sides
-----> multiply by both sides
congruent
proportional
supplementary
Thank you