In the graph above, the cordinates of the vertices of quadrilateral QPRS are Q(2,4), P(2,4), R(3,1), and S(1,1). If quadrilateral QPRS is reflected across the x-axis to create quadrilateral GHIJ l, find tge coordinates of point j

Answers

Answer 1

Answer: In the following graph, the coordinates of the vertices of quadrilateral QPRS are Q(2,4), P(4,4), R(3,1), and S(1,1). If quadrilateral QPRS is reflected across the x-axis to create quadrilateral GHIJ l, these coordinates are G(1,-1), H(3,-1) , I(2,-4) and J(4,-4).

Answer 2

Answer:

Answer:

As, when Graph is reflected across the X axis

1. The two, Image which is Quadrilateral G H I J and Pre image which is Quadrilateral QPRS will be congruent.

2. Distance from X axis to each of the vertices of Quadrilateral QPRS will be same as distance from each of the vertices of Quadrilateral G H I J from X axis.

As, Quadrilateral QPRS lies in first Quadrant, so when it is reflected across X axis, it moves in Second Quadrant which is Quadrilateral GHIJ.

Q→→G, P→→H, R→→I, S→→J.

Coordinates of S=(1,1)

Coordinates of J=(-1,1)

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Square root of x to the 6th power over y to the 4th power

Answers

√((x^6)/(y^4))

x^6 indicates x to the sixth power, the same goes for y^4.

Need help with all please??!!!!

Answers

9. $V = (√(3))/(2)a^(2)h$
$V = (√(3))/(2)(4)^(2)(8)$
$V = (√(3))/(2)(16)(8)$
$V = (√(3))/(2)(128)$
$V = (128√(3))/(2)$
$V = 64√(3)\ cm^(3)$
The answer is D.

10. V = ¹/₃πr²h
V = ¹/₃(3.14)(6)²(10)
V = ¹/₃(3.14)(36)(10)
V = ¹/₃(3.14)(360)
V = ¹/₃(1130.4)
V = 376.8 cm³
The answer is C.

11. V = ¹/₃πr²h
V = ¹/₃(3.14)(6)²(10)
V = ¹/₃(3.14)(36)(10)
V = ¹/₃(3.14)(360)
V = ¹/₃(1130.4)
V = 376.8 cm³
The answer is C.

12. V = 1¹/₃πr³
V = 1¹/₃(3.14)(3)³
V = 1¹/₃(3.14)(27)
V = 1¹/₃(84.78)
V = 113.04 cm³
The answer is C.

13. V = 1¹/₃πr³
V = 1¹/₃(3.14)(12)³
V = 1¹/₃(3.14)(1728)
V = 1¹/₃(5425.92)
V = 7234.56 cm³
The answer is A.

14. S = 4πr²
  324π = 4(3.14)(r)²
324(3.14) = 4(3.14r²)
1017.36 = 12.56r²
12.56 12.56
  81 = r²
  9 = r

V = 1¹/₃πr³
V = 1¹/₃(3.14)(9)³
V = 1¹/₃(3.14)(729)
V = 1¹/₃(2289.06)
V = 3052.08
The answer is D.

15. The answer is A.
16. The answer is A.
17. The answer is B.
18. The answer is C.

13. c
14. d
15. b
Sorry if I am not correct I'm only in 6th grade

The points (-2, 4) and (1,r) lie on a line with slope 3. Find the missing coordinate r.

Answers

Answer:

-9

Step-by-step explanation:

Slope = (y2 - y1)/(x2 - x1)

(r - 11)/(4 - (-1)) = (r - 11)/5

So, (r - 11)/5 = -4

r - 11 = -20

r = -9

I dont know wht

way you are doing this but hope it helps

Mrs. Stephan took her children to pick out pumpkins. Carter picked out a pumpkin priced $20, andIsabelle picked out a pumpkin priced at $13. How much did Mrs. Stephan pay for both pumpkins, including
7% sales tax?

Answers

Answer:

$35.31

Step-by-step explanation:

In this question, we're trying to find the total cost of the pumpkins (including tax).

We know that Carter picked a $20 pumpkin, while Isabelle picked a $13 pumpkin.

We also know that the sales tax is 7%

To get your answer, we would add the prices of the pumpkin and find the tax price to get our final answer.

Find the total cost:

20 + 13 = 33

Since the sales tax is 7%, we would multiply 33 by 1.07:

33 · 1.07 = 35.31

Mrs. Stephan paid $35.31 for the pumpkins and sales tax.

Apples are on sale for $1.20 a pound. Logan bought 3/4 of a pound. How much money did he spend on apples

Answers

What I did was turn ¾ in to a fraction (which is 75%) then turned it into a decimal (.75)
then I multiplied .75 by 1.20 and .9
So she spent 90 cents on apples
Hope I helped :)

$(3)/(4) * 1.20 = (3.6)/(4) = \huge{\boxed{0.9}}$

He spend 90 cents on apples.

In triangle ABC, the measure of angle B is 90 degrees, BC=16, and AC=20. triangle DEF is similar to triangle ABC, where vertices D, E, and F corresponds to vertices A, B, and C, respectively, and each side of triangle DEF is 1/3 the length of the corresponding side of triangle ABC. what is the value of sinF?(please show your work)

Answers

The third side of triangle ABC is AB. Using the Pythagorean Theorem, its length is 12.
12² + 16² = 20²

∠F is congruent to ∠C and so the sin(∠F) = sin(∠C)

The sin(∠C) = opposite/hypotenuse
= |AB| / |AC|
= 12/20
= 3/5
= 0.6

So the answer is 0.6.

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