Dr. Smith wants to use only students with "normal" IQ in his experiment. He defines "normal" as anyone who scores in the middle 50% of IQ scores. Using this rule, what will be the lowest IQ score that could be included in the study and what would be the highest IQ score that could be included in the study? You know that the population of IQ scores are normally distributed, have µ = 100, and have σ = 15. (1 point)

Answers

Answer 1
Answer:

Answer:

Lowest IQ: 89.875

Highest IQ: 110.125

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 15.

He defines "normal" as anyone who scores in the middle 50% of IQ scores. Using this rule, what will be the lowest IQ score that could be included in the study and what would be the highest IQ score that could be included in the study?

The middle 50% is the interval from the 25th percentile to the 75th percentile.

Lowest IQ:

This is the measure in the 25th percentile. That is X when Z has a pvalue of 0.25. So it is Z = -0.675

Z = (X - \mu)/(\sigma)

-0.675 = (X - 100)/(15)

X - 100 = 15*(-0.675)

X = 89.875

Highest IQ:

This is the measure in the 75th percentile. That is X when Z has a pvalue of 0.75. So it is Z = 0.675

Z = (X - \mu)/(\sigma)

0.675 = (X - 100)/(15)

X - 100 = 15*(0.675)

X = 110.125


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A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of π.)452.16 cm3

840.54 cm3

1,055.04 cm3

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Answers

Given:
Cylinder: height = 16 cm ; radius = 5 cm
cone: height = 12 cm ; radius = 4 cm

Volume of cylinder = 3.14 * (5cm)² * 16cm = 1,256 cm³
Volume of cone = 3.14 * (4cm)² * 12cm/3 = 200.96 cm³

Volume of air space = 1256 cm³ - 200.96 cm³ = 1,055.04 cm³ 
Cylinder: height = 16 cm ; radius = 5 cm
cone: height = 12 cm ; radius = 4 cm

Volume of cylinder = 3.14 * (5cm)² * 16cm = 1,256 cm³
Volume of cone = 3.14 * (4cm)² * 12cm/3 = 200.96 cm³

Volume of air space = 1256 cm³ - 200.96 cm³ = 1,055.04 cm³ 

Point C is the center of the circle. angle ACB measures 49. What is the of arc ADB

Answers

If arc ADB is that portion of the circle that is not arc AB, then its measure is ...

... 360° -49° = 311°

_____

The sum of the measures of the arcs of a circle is 360°.

A set of data whose histogram is extremely skewed yields a sample mean and standard deviation of 69.5 and 10.75, respectively. What is the minimum percentage of observations that:A. are between 48 and 91.

and

B. are between 37.25 and 101.75

Answers

I am a beautiful person who can help you with the new one of those who are interested

Use the distance formula to find the distance between (−8, 2.5) and (0, −4.5).d = StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot
1. Substitute coordinates: d = StartRoot (negative 8 minus 0) squared + (2.5 minus (negative 4.5)) squared EndRoot
2. Simplify parentheses: d = StartRoot (negative 8) squared + (7) squared EndRoot
3. Evaluate powers: d = StartRoot 64 + 49 EndRoot
4. Simplify.
What is the distance between (–8, 2.5) and (0, –4.5)? Round to the nearest hundredth.

d ≈

Answers

The distance between points (- 8, 2.5) and (0, - 4.5) is,

⇒ d = 10.67

What is Coordinates?

A pair of numbers which describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines is called the coordinates.

Given that;

Two points are,

⇒ (- 8, 2.5) and (0, - 4.5)

Hence, The distance between (- 8, 2.5) and (0, - 4.5) is,

d = √ (- 8 - 0)² + (2.5 + 4.5)²

d = √ 64 + 7²

d = √64 + 49

d = √114

d = 10.67

Thus, The distance between points (- 8, 2.5) and (0, - 4.5) is,

⇒ d = 10.67

Learn more about the coordinate visit:

brainly.com/question/24394007

#SPJ6

Answer: B.10.63

Step-by-step explanation:

Ashley's Internet service is terribly unreliable. In fact, on any given day, there is a 25 % chance that her Internet connection will be lostat some point that day. What is the probability that her Internet service is not broken for five days in a row? Enter a fraction or round
your answer to 4 decimal places, if necessary.

Answers

Answer:

The probability that her internet service will not be broken for five days in a row is 243/1024

Step-by-step explanation:

Here, we want to calculate the probability that her internet service is not broken for five days in a row

Let the event that her internet will be broken be B and the event that her internet will not be broken be N

P(B ) = 25% = 0.25

P(N) = 1-0.25 = 0.75 = 3/4

Thus, the probability that her internet is not broken for five days in a row = P(N) * P(N) * P(N) * P(N) * P(N)

= 3/4 * 3/4 * 3/4 * 3/4 * 3/4 = 243/1024

What is the measure of angle D? Enter your answer as a decimal, round only your final answer to the nearest hundredth.

Answers

Answer: Angle D= 0.51 radians or 29.05°

Step-by-step explanation:

For this problem, we can use our trigonometry to find the measure of angle D.

Since this is a right triangle, we know we can use sine, cosine, and tangent. We are focusing on angle D, so we would see which trigonometric function best fits angle D. Looking at where 25 ft and 45 ft are labeled, we can use tangent. Tangent of opposite/adjacent. Now that we know this, we can set up an equation. Let's use θ in place for angle D.

tan(θ)=25/45

tan(θ)=5/9

Since we want to find θ, we would do inverse tangent.

θ= tan^-^1((5)/(9) )

θ=0.507

θ=0.51

This answer is in radians. In degrees, it is 29.05°.