Answer:
Step-by-step explanation:
hat was the first number created?
For example, the Arabic numeral system we're all familiar with today is usually credited to two mathematicians from ancient India: Brahmagupta from the 6th century B.C. and Aryabhat from the 5th century B.C. Eventually, numbers were necessary for more than simply counting things.
Answer:
0
Step-by-step explanation:
Answer:
80 cm
Step-by-step explanation:
This is because the shape is a square, and area is width x height x length.
Since the shape is a square, all sides are the same therefore the answer is 80 cm.
Answer:
Domain: all real numbers
Range: all real numbers
Step-by-step explanation:
There is no restriction on the variable x, so the domain is all reals.
Similarly, the range is all reals as the graph of this function is a line that is neither vertical nor horizontal.
Answer:
2 successes = 80/243
0 successes = 32/243
at least 3 successes = 51/243
Step-by-step explanation:
Lets suppose we had the following sequence of 5 throws:-
2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws
Probability of this is
1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243
There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).
So Prob(2 successes) = (8/243) * 10 = 80/243
Prob ( No successes) = (2/3)^5 = 32/243
Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3
4/243 * 10 = 40 / 243
Probability of 4 successes = (1/3)^4 * 2/3 * 5C4
= 10/243
Probability of 5 success = (1/3)^5 = 1 / 243
Prob(at least 3 successes) = 51/243
Answer:
2 successes = 80/243
0 successes = 32/243
at least 3 successes = 51/243
Step-by-step explanation:
Lets suppose we had the following sequence of 5 throws:-
2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws
Probability of this is
1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243
There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).
So Prob(2 successes) = (8/243) * 10 = 80/243
Prob ( No successes) = (2/3)^5 = 32/243
Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3
4/243 * 10 = 40 / 243
Probability of 4 successes = (1/3)^4 * 2/3 * 5C4
= 10/243
Probability of 5 success = (1/3)^5 = 1 / 243
Prob(at least 3 successes) = 51/243