Answer: The answer is A. Coincides with
Step-by-step explanation:
The given first-order differential equation is linear in the indicated dependent variable because it matches the standard form of a linear first-order differential equation, a1(x) dy/dx + a0(x)y = f(x).
First, let us review what a linear first-order differential equation is. Ais a differential equation that can be written in the form:
a1(x) dy/dx + a0(x)y = f(x)
Now, let us compare the given differential equation to the standard form of a linear first-order differential equation. The given differential equation is:
a1(x) dy/dx + a0(x)y
As we can see, the given differential equation matches the standard form of a linear first-order differential equation. Therefore, we can conclude that the given differential equation is linear in the indicated dependent variable.
In conclusion, the given first-order differential equation is linear in the indicated dependent variable because it matches the standard form of a linear first-order differential equation, a1(x) dy/dx + a0(x)y = f(x).
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Answer:
a = 3
Step-by-step explanation:
f(x) = a(bˣ)
At x = 0
f(0) = a(b⁰)
f(0) = a(1)
f(0) = a
From the graph
f(0) = 3
Therefor
a = 3
(3, 0)
(0, 3)
(0, -3)
(-3, 0)
The point B is located at (3, 0). Therefore option B is the correct answer.
On graph A, B, C, D and E points are given.
Graph is a mathematical representation of a network and it describes the relationship between lines and points. A graph consists of some points and lines between them. The length of the lines and position of the points do not matter.
The numbers on a coordinate grid are used to locate points. Each point can be identified by an ordered pair of numbers; that is, a number on the x-axis called an x-coordinate, and a number on the y-axis called a y-coordinate. Ordered pairs are written in parentheses (x-coordinate, y-coordinate).
Here, on the point B is located at (3, 0).
The point B is located at (3, 0). Therefore option B is the correct answer.
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Point B is located at (0, -3). When both x and y coordinates are positive,it lies in the first quadrant. If both are negative, it lies in the thirdquadrant. If x is negative and y is positive, it is in the second quadrant. If xis positive and y is negative, it is in the fourth quadrant.
work out
∛15.76 - 4.6³ ÷2.5/3
Answer:
-10.47413972 or -10.47
Step-by-step explanation:
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Answer:
-10.47 is the answer
Step-by-step explanation:
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