Which of these properties of a rigid transformation is exclusive to translations?The measures of the angles and sides in the preimage are preserved.

The points in the preimage lie in the same plane as the points in the image.

All the points in the preimage are shifted the same distance.

The orientation of sequences of points in the preimage are always preserved.

Answers

Answer 1

Answer: The properties of a rigid transformation is exclusive to translations is teh phrase "The points in the preimage lie in the same plane as the points in the image". The rest of the statements do not answer the question above.

Answer 2

Answer:

Answer with explanation:

There are four kind of Rigid transformation that can take place in a two dimensional or Three dimensional geometrical Shape

1. Rotation

2. Reflection

3.Dilation

4. Translation

When we translate a geometrical shape , the Preimage , shifts from one position to another position in the plane in which it lies ,without changing the shape ,size ,and Interior angle of the PreImage.

→→I have described first three properties ,which are true to translation by taking a triangle ,having vertices , (0,0), (0,1) and (1,0).

Now, translating the triangle , by 1 unit right and 1 unit up,got the triangle having vertices, (1,1),(1,2) and (2,1).

Option 4 : The orientation of sequences of points in the pre image are always preserved, is the property of a rigid transformation that appears exclusive to translations.

Related Questions

Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds. Let p represent the number of pounds of peanuts needed to make the new mixture, and let m represent the number of pounds of the 80% almond-20% peanut mixture. What is the system that models this situation? Which of the following is a solution to the system: 2 lb peanuts and 3 lb mixture; 2.5 lb peanuts and 2.5 lb mixture; 4 lb peanuts and 1 lb mixture? Show your work.
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2. Yumi takes hour to complete 50 math problems. Eric is able to complete 48math problems in hour. Which student can complete math problems at agreater rate of problems per hour?
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What multiplies to -300 and adds to 13

P10.
2
In parallelogram PQRS, Ô = 114º,
PT bisects Ê and TS bisects ŝ.
Prove that PT I ST.
R

Answers

Answer:

PQ R s parallelogram

< Q = < s = 114

< P = 180 _ 114 = 66

<2 = 66 / 2 = 33

< I = 114 / 2 = 5 7

< I + < 2 = 3 3 + 57 = 90

< ( STP ) = 90

TP I ST

A rectangular pool measures 10m by 5m. A deck, of uniform width, is to be built all the way around the pool such that the total area of the pool and deck will be126m2 . Set up and solve a quadratic equation to determine the width of the deck.

Answers

Answer:

The width of the deck is 2m .

Step-by-step explanation:

Let the width of the pool be represented by w. As stated in the problem a deck of uniform width is to be built so the total width of the pool and deck will be w+w = 2w.

Now the total dimensions can be taken as

10m+ 2w and 5m + 2w of both the pool and deck.

Area = length * breadth

126m ²= (10m+ 2w) ( 5m + 2w )

126= 50 + 30 w+ 4w²

0= 50 -126+ 30 w+ 4w²

0 = 30 w+ 4w²- 76

Taking 2 as common

0= 2( 15 w+ 2w² - 38)

2w²+ 15 w - 38= 0

The above equation is the quadratic equation and can be solved as follows.

a= 2 , b= 15 and c= -38

b= -b±√b²- 4ac/2a

Putting the values

b= - 15±√15²- 4( 2)(-38)/2(2)

b= - 15± 23/4

b= - 38/4 or 8/4

b= 2 m

The width cannot be negative so we ignore the negative value

The width of the deck is 2m .

The can be checked by putting the value in the original equation.

126m ²= (10m+ 2w) ( 5m + 2w )

126m ²= (10m+ 2(2)) ( 5m + 2(2) )

126m ²= (10m+ 4) ( 5m + 4 )

126m ²= 14*9

126m ²= 126m ²

Joe will go to the swimming pool on 20 different days this month. • a one-day pass to the pool is $2.25. • a monthly pass to the pool is $30.00. how much money will joe save by buying a monthly pass

Answers

Joe will save 20 dollars buying a monthly pass

Adding which terms to 3x2y would result in a monomial? Check all that apply.3xy

–12x2y

2x2y2

7xy2

–10x2

4x2y

3x3

Answers

Adding and subtracting amonomial requires having the same variables. No matter how big or small theircoefficient is, if their variables do not match, they cannot be added or subtracted.The crucial part in adding or subtracting monomials is their sign. If the signsare the same, retain the sign. If the signs are different, subtract and keepthe sign of the larger number.

3x2y + 3xy (cannot be added)
3x2y + (–12x2y) = -9x2y
3x2y + 2x2y2 (cannot be added)
3x2y + 7xy2 (cannot be added)
3x2y + (–10x2) (cannot be added)
3x2y + 4x2y = 7x2y
3x2y + 3x3 (cannot be added)

Answer:

B and F would be your correct answers

The multiplication property of equality could be used to solve which of the following equations?(x + 2)(x - 3) = 0
m + 7 = -12
b ÷ (-2) = 18
-3 + y = 7

Answers

b ÷ (-2) = 18
hope it helps

well
first one doesn't need that property
2nd one needs subtraction property of equality
third one can use it
fourth one needs addition property of equality

3rd one is answer
b/-2=18 is answer

i want to find out how many fish food boxes can fit into the shipping box my answer is 36 but i need help finding out how many and if im right {25 PTS}

Answers

Answer:

you have to

Step-by-step explanation:

Answer:

2700 I think?

Step-by-step explanation:

Um 3/ 1/4 = 12 and 3 3/4 / 1/4 = 15 so 15 * 12 * 15 is 2700

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