b^2+c^2<a^2 just took test
Answer:
To find the area of a trapezoid, we can use the formula:
Area = (1/2) × (sum of bases) × (height)
In this case, the bases are 6 cm and 2 cm, and the height is the distance between them, which we can find using the Pythagorean theorem:
height² = (side)² - (difference of bases/2)²
height² = 5.4² - (2-6/2)²
height² = 29.16 - 9
height² = 20.16
height = √20.16
height ≈ 4.49 cm
Now we can plug in these values to find the area:
Area = (1/2) × (6 + 2) × 4.49
Area = 4 × 4.49
Area = 17.96 cm²
Therefore, the area of the trapezoid is approximately 17.96 square centimeters.
Step-by-step explanation:
What is the interquartile range of the data?
2
3
4
6
the interquartile range of the data is:
4
We are given a data set as:
0, 2, 4, 0, 2, 3, 2, 8, 6
On arranging the data in the ascending i.e. increasing order is given by:
0 0 2 2 2 3 4 6 8
The minimum value of data set=0
Maximum value of data set is: 8
Range of data set= Maximum value-Minimum value
i.e. Range= 8-0
i.e. Range= 8
Also, Median of set is the central tendency of the data and is given by:
Median= 2
Lower set of data is:
0 0 2 2
Hence, The median of lower set of data is the lower quartile or first quartile.
i.e.
Hence,
Hence, Lower quartile=1
Similarly upper set of data is:
3 4 6 8
Hence, The median of upper set of data is the upper quartile or third quartile.
i.e.
Hence,
Hence, Upper quartile=5
Hence, the interquartile range(IQR) is given by:
IQR=Upper quartile-Lower quartile
IQR=5-1
IQR=4
y = 1 over 4x − 8
y = −4x − 8
y = −1 over 4x − 8
Answer
Step-by-step explanation:
31.26 s
31 s
31.256 s