Answer:
Equation 3
Step-by-step explanation:
Lets see which of the functions has -2 as a zero root. We will go in order:
(1) (-2)^4 - 3(-2)^3 + 3(-2)^2 -3(-2) + 2 = 16 - 3(-8) + 3(4) + 6 +2 = 16 +24 +12 + 6 +2 =60 >0
So, (1) is wrong!
(2) (-2)^4 + 3(-2)^3 + 3(-2)^2 - 3(-2) - 2 = 16 - 24 + 12 + 6 - 2 =34 - 26 = 8 > 0
(2) is also wrong!
(3) (-2)^4 + 3(-2)^3 + 3(-2)^2 +3(-2) + 2 = 16 - 24 + 12 - 6 + 2 = 30 -30 = 0
The zero root x=-2 fits, what about x=-1?
(-1)^4 + 3(-1)^3 + 3(-1)^2 +3(-1) + 2 = 1 - 3 + 3 - 3 + 2 = 6 - 6 = 0
So, equation (3) fits both!
Finally, lets see (4):
(-2)^4 - 3(-2)^3 - 3(-2)^2 + 3(-2) + 2 = 16 + 24 - 12 - 6 + 2 = 42 - 18 = 24 > 0
So, (4) is also wrong.
Only equation 3 fits both zero roots!
The quartic function with x=-1 and x=-2 real roots is x^4+6x^3 +12x^2+12x+4. Quartic functions are polynomial functions of degree 4; quadratic equations resources also help understand the concept. In essence, finding roots of quartic functions follow the same logic as that of quadratic functions.
The subject matter pertains to quartic functions in mathematics. Quartic functions are polynomial functions with a degree of 4. From the question, the given zeros are x=-1 and x=-2, having multiplicity of 2 each (since there are only two real zeros). Thus, the quartic function with these zeros will be (x+1)^2*(x+2)^2. This can be expanded to x^4+6x^3 +12x^2+12x+4.
Exemplifying the relevance of The Solution of Quadratic Equations, normally known as second-order polynomials or quadratic functions, such equations can also be used to find zeros of the functions when set to equal zero. In this scenario, quartic functions are a degree higher, but the same principle applies in finding the roots when the equation is set equal to zero.
#SPJ3
−7.8(x+6.5)=−25.74
Enter your answer, as a decimal, in the box.
42 ³/₄ ft²
Given:
Question:
What is the area?
The Process:
A gardening box is rectangular. Units of length that are the same, i.e., in feet.
The perimeter formula is as follows:
It can also be written as follows:
Step-1: calculate the width
Let's use the formula above.
Step-2: calculate the area
The area formula is as follows:
Thus, the area of a gardening box is
Keywords: a gardening box, has a perimeter, 27 1/2 feet, the length, width, 9 feet, what is the area?, rectangular, formula
A) 2n
B) n + 3
C) 2n + 1
D) -n + 3
Answer:The answer is D
Step-by-step explanation: for the first term (1)
-(1)+3=2. Whist is the correct number for the 1st term
-8, -5, -2, 1, 4,...
Answer:
then 7,10,13 and so one so forth
Step-by-step explanation:
you are subtracting three as you go on.
Answer:
3(u^2 +u-3)
-------------------
u(u-3)^2
Step-by-step explanation:
u 1
---- + -------
u-3 u
-------------------------
u-3
----------
3
Get a common denominator for the numerator
u *u 1(u-3)
---- + -------
(u-3)u u(u-3)
-------------------------
u-3
----------
3
u *u + (u-3)
-----------
(u-3)u
-------------------------
u-3
----------
3
Now use copy dot flip
u *u + (u-3) 3
----------------- * -------------
(u-3)u u-3
3(u^2 +u-3)
-------------------
u(u-3)^2