Answer:
v = 54 m/s
Explanation:
Given,
The maximum height of the flight of golf ball, h = 150 m
The velocity at height h, u = 0
The velocity of the golf ball right before it hits the ground, v = ?
Using the III equations of motion
v² = u² + 2gh
Substituting the given values in the above equation,
v² = 0 + 2 x 9.8 x 150 m
= 2940
v = 54 m/s
Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s
The impulse-theorem states that the change in momentum of an object is equal to the impulse exerted on it
Explanation:
The impulse-theorem states that the change in momentum of an object is equal to the impulse exerted on it.
Mathematically, we have:
- The impulse is defined as the product between the force exerted (F) and the duration of the collision ():
- The change in momentum is equal to the product between the mass of the object (m) and the change in velocity ():
So, the theorem can be written as
This theorem can be proved by using Newton's second law. In fact, we know that
(1)
where a is the acceleration of the object. However, we can re-write the acceleration as the rate of change of velocity:
Therefore, (1) becomes:
And by re-arranging,
Which is exactly the formula of the impulse theorem.
Learn more about impulse and momentum:
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