PHYSICS HIGH SCHOOL

When two point charges are a distance d apart, the magnitude of the electrostatic force between them is F. If the distance between the point charges is increased to 3d, the magnitude of the electrostatic force between the two charges will be

Answers

Answer 1

Answer:

Answer:

The magnitude of the electrostatic force decreases by a factor 9

Explanation:

The electrostatic force between two charges is given by:

$F=k(q_1 q_2)/(d^2)$

where

k is the Coulomb's constant

q1 and q2 are the two charges

d is the distance between the two charges

We see that the magnitude of the force is inversely proportional to the square of the distance. If the distance is increased to 3d: d' = 3d, the new electrostatic force would be:

$F'=k(q_1 q_2)/((d')^2)=k(q_1 q_2)/((3d)^2)=(1)/(9) k(q_1 q_2)/(d^2)=(F)/(9)$

So, the electrostatic force decreases by a factor 9.

Answer 2

Answer: Decreased by a factor of 9

Right answer: The weight of the air displaced is less than the volume of the balloon

A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner (which is the motor of the balloon and responsible for its elevation) heats the liquid propane to a gaseous state to generate a huge flame, thus heating the air mass inside the balloon. In this way, its density is modified with respect to the air that surrounds it, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.

Now, if we know that the density of a body $d$ is directly proportional to its mass $m$ and inversely proportional to its volume $V$ :

$d=(m)/(V)$

We can deduce that

by increasing the volume of the body, its density will decrease.

This is proof of Archimedes' Principle:

A body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.

In this case the fluid is the air outside. So, the warm air inside the balloon, being less dense, will weigh less than the outside air and therefore will receive an upward pushing force or thrust that will make the balloon ascend.

Which of the following happens in a heat pump?a. the compressor increases the pressure and temperature pf the refrigerant

b. the compressor blows cold refrigerant into the room

c none of the above

Answers

option c. none of the above

The heat pump is like an air conditioning unit. There is an air compressor inside it,the function is to convert power (using electric, diesel, gasoline) into potential energy stored in pressurized air (compressed air).By any means and methods, the prs

When an object is at a distance of twice the focal length from a concave lens, the image produced is virtual and smaller than the object. What happens to the image if the object is shifted closer to the lens to a point one focal length away from it?The image produced is virtual and enlarged.
The image produced is virtual and smaller than the object.
The image produced is real and enlarged.
The image produced is real and smaller than the object.
The image produced is virtual and of the same size as the object.

Answers

Answer:

The image produced is virtual and smaller than the object.

Explanation:

For concave lens we know that

$(1)/(d_i) + (1)/(d_o) = (1)/(f)$

here we have

$(1)/(d_i) + (1)/(2f) = -(1)/(f)$

$(1)/(d_i) = - (3)/(2f)$

$d_i = -(2f)/(3)$

Magnification will be given as

$M = (d_i)/(d_o)$

$M = -2/3$

so image will be virtual and formed behind the lens

Now the object position is shifted to new position at distance of focal length

now again we will have

here we have

$(1)/(d_i) + (1)/(f) = -(1)/(f)$

$(1)/(d_i) = - (2)/(f)$

$d_i = -(f)/(2)$

Magnification will be given as

$M = (d_i)/(d_o)$

$M = -1/2$

So again we will have virtual image with magnification 1/2

so here size of image is less than object size by factor of 1/2 and it is virtual

The right answer for the question that is being asked and shown above is that: "The image produced is virtual and of the same size as the object." the image if the object is shifted closer to the lens to a point one focal length away from it is that The image produced is virtual and of the same size as the object.

Which equation describes the sum of the two vectors plotted below?

Answers

Final answer:

The sum of two vectors A and B is a resultant vector R, where R = A + B. If vectors A and B are plotted with their tails at the origin and heads at points (x1, y1) and (x2, y2), respectively, the resultant vector R ends at point (x1+x2, y1+y2). This represents the sum of the individual components of vectors A and B.

Explanation:

In vector addition, the equation for the sum of two vectors A and B can be generally represented as R = A + B, where R is the resultant vector. If the vectors are plotted with their tails at the origin and their heads ending at points (x1, y1) for Vector A and (x2, y2) for Vector B, the resultant vector, R, will end at the point (x1+x2, y1+y2). In other words, the components of the resultant vector are simply the sum of the components of the original vectors.

Learn more about Vector Addition here:

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Answer:

R=-x-4y

Explanation:

Because i said so

What determines the composition of a rock

Answers

Is determined by the percent of constituent of minerals and elements contained within it.

Composition of a rock is determined by the percent of constituent of minerals and elements contained within it.

Explanation:

The composition of a rock is decided by the % of the constituent minerals and components contained inside it.

The minerals that form up rocks have outlined chemical compositions and rigid atomic structures. once daylight strikes the rock's surface, the composition and atomic structure of the various minerals management the wavelengths they absorb or replicate.

Energy is measured in watts and work is measured in joules. true or false?