How would you solve the following geometry problem?:∆PQR, find the measure of ∡P.

In Triangle PQR where angle Q is a right angle. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown.

Answers:
30.4°

35.9°

54.1°

59.6°

What I did:
equation: tan(x) = 33.8/57.6
tan(x)=0.56
But I know that isn't correct.

Answers

Answer 1

Answer: What you did is correct. However the one you get is the tangent value of x. you have to find out the tan inverse of that value to find out the actual degree.

tan(x) = 33.8 / 57.6
tan(x) = 0.587
x = tan^-1 (0.587)
x = 30.4 degrees

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Thank you, please show me the steps.

Answers

V=(1/3)hpir^2
d/2=r
2.75/2=1.375
to make volume 4 times more
multiply height by 4 or multiply radius by 2
example
find current cup volume
V=(1/3)2.75pi1.375^2=2.2057291666666pi

if we times height by 4
3.5*4=14
V=(1/3)14pi1.375^2=8.822916666666666666pi

if we times radius by 2
1.375*2=5.5
V=(1/3)3.5pi5.5^2=8.822916666666666666pi

we can show it is 4 times by
8.822916666666666666pi/2.2057291666666pi= 3.99999 close enough
dimentions are

diameter of 2.75in and height of 11in or
diameter of 5.5in and height of 3.5 in

Jason jumped of a cliff into the ocean . His height as a function off time could be models as h(t)=16tsquared + 16t + 480 where t is the time in seconds and h is height in feet. How long did it take Jason to reach his maximum height

Answers

I see that you are in high school, and I'm hoping that you've been introduced
to differential calculus, because I don't know how to answer this question without
using it.

We're told that Jason's height above the water is H(t) = -16t² + 16t + 480 .
We can observe many things from this equation:
-- Up is the positive direction; down is the negative direction.
-- The acceleration of gravity is 32 ft/sec² .
-- Jason jumps upward from the cliff, at 16 ft/sec .
-- The cliff is 480-ft above the water.
(This tells us why the question is only concerned with his maximum height,
and then it ends ... 480-ft is one serious cliff, and what happens after the
peak of his arc is too gruesome to contemplate.)

In any case, his vertical velocity is the first derivative, with respect to time,
of his height above the water.

   V = -32 t + 16

At the peak of his arc, where gravity takes over, his velocity changes from
upward to downward, and it's momentarily zero.

   0 = -32t + 16

Add 32t to each side: 32t = 16

Divide each side by 32: t = 1/2 second

His height at that instant is    H(0.5) = -16(0.5)² + 16(0.5) + 480 =

   4-ft above the cliff, 484-ft above the water,

and then he begins falling from that altitude.

The duration of his dive is 484 = 16 t²
   t = √(484/16) = 5.5 seconds

and he hits the water at V = a t = (32) x (5.5) = 176 ft/sec = exactly 120 mph

Jason was good man ... a good student, and always kind to everyone he met.
He will certainly be missed.

Consider the exponential function f(x) = 1/5(15x). What is the value of the growth factor of the function?a.1/5
b.1/3
c.5
d.15

Answers

Answer:

Option: d is the correct answer.

d. 15

Step-by-step explanation:

We are given a exponential function as:

$f(x)=(1)/(5)(15^x)$

We know that in general a exponential function is represented by:

$f(x)=ab^x$

where a is the initial amount and b represents a growth factor if it is strictly greater than 1 and a decay factor if 0<b<1

Hence, the value of the growth factor of the function is:

d. 15

The answer would have to be 15.

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Answers

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